11^0 is 1.
11^2= 121
121/1= 121
Final answer: 121
1.031 rounded to the nearest tenth is 1.0
The perimeter of a shape is the sum of the lengths of its sides.
So, to find the perimeter of this quadrilateral, all we have to do is add the side lengths and simplify.
(x² - 6) + (2x + 5) + (x² - 3x) + (4x² + 2x)
x² + x² + 4x² + (-3x) + 2x + 2x + (-6) + 5
6x² + (-3x) + 2x + 2x + (-6) + 5
6x² + x + (-6) + 5
6x² + x + (-1)
6x² + x - 1
So, the perimeter of the quadrilateral is the quantity (6x² + x - 1).
Hope this helps!
Answer:
the correct anwser is -3 and if you need anymore help the website i use is
Step-by-step explanation:
https://www.tiger-algebra.com
