Answer:
7.1 moles Cl₂
Explanation:
To solve this problem we will use <em>Avogadro's number </em>(Aₙ), which tells us how many molecules (or atoms) are present in 1 mol of any given substance
Aₙ = 6.023 x 10²³ molecules/mol
With that in mind now we proceed to convert molecules into moles:
4.28 x 10²⁴ molecules Cl₂ ÷ 6.023 x 10²³ molecules/mol = 7.1 moles Cl₂
How many carbon atoms are there in a 1.3-carat diamond? Answer: 1.3 x 10^22 C atoms...
If a 1 carat = 0.20 g ... then 0.3 carat = 0.20 / 0.3 = 0.06 g
Thus, 1.3 carat = 0.26g
Find the moles first:
Moles= Grams / Mm of C
0.26 / 12.011 = 0.0216 mols of C
Atoms = Moles * Avogadro's number (6.022*10^23)
0.0216 * 6.022*10^23 = 1.3*10^22 C atoms
Hope this helps! :)
Answer: ![5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.Explanation:The balanced chemical equation is: [tex]2NH_4NO_3(s)\rightarrow 2MgO(s)+4NO_2(g)+O_2(g)](https://tex.z-dn.net/?f=5.6dm%5E3%5B%2Ftex%5B%20of%20gas%20is%20produced%20when%200.1%20moles%20of%20magnesium%20nitrate%20is%20decomposed.%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EExplanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EThe%20balanced%20chemical%20equation%20is%3A%0A%3C%2Fp%3E%3Cp%3E%5Btex%5D2NH_4NO_3%28s%29%5Crightarrow%202MgO%28s%29%2B4NO_2%28g%29%2BO_2%28g%29)
According to stoichiometry :
2 moles of 
produce = 4 moles of 
gas and 1 mole of 
gas
2 moles of produce = 5 moles of gas
Thus 0.1 mole of produce =
of gas
Volume of gas produced = 
Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.
Cl2O but the two is a little two after Cl
