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Kitty [74]
3 years ago
13

Please please help me solve this, I have a test and only 20 mins left T-T​

Chemistry
1 answer:
Ann [662]3 years ago
7 0

Answer: 5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.Explanation:The balanced chemical equation is:
[tex]2NH_4NO_3(s)\rightarrow 2MgO(s)+4NO_2(g)+O_2(g)

According to stoichiometry :

2 moles of NH_4NO_3 produce = 4 moles of NO_2 gas and 1 mole of O_2 gas

2 moles of NH_4NO_3 produce = 5 moles of gas

Thus 0.1 mole of NH_4NO_3 produce =\frac{5}{2}\times 0.1=0.25moles  of gas

Volume of gas produced = moles\times {\text {Molar volume}}=0.25moles\times 22.4dm^3/mol=5.6dm^3

Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.

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