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Kitty [74]
3 years ago
13

Please please help me solve this, I have a test and only 20 mins left T-T​

Chemistry
1 answer:
Ann [662]3 years ago
7 0

Answer: 5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.Explanation:The balanced chemical equation is:
[tex]2NH_4NO_3(s)\rightarrow 2MgO(s)+4NO_2(g)+O_2(g)

According to stoichiometry :

2 moles of NH_4NO_3 produce = 4 moles of NO_2 gas and 1 mole of O_2 gas

2 moles of NH_4NO_3 produce = 5 moles of gas

Thus 0.1 mole of NH_4NO_3 produce =\frac{5}{2}\times 0.1=0.25moles  of gas

Volume of gas produced = moles\times {\text {Molar volume}}=0.25moles\times 22.4dm^3/mol=5.6dm^3

Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.

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7 0
2 years ago
To make 2.00 L of 0.300 M sulfuric acid, how many mL of a 1.00 M stock solution should be used?
Tamiku [17]
We are given with
M1 = 1.00 M

M2 = 0.300 M
V2 = 2.00 L

We are asked to get V1

Using material balance
M1 V1 = M2 V2
Substituting the given values
1.00 V1 = 0.300 M (2.00 L)
V1 = 0.600 L or 600 mL
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3 0
3 years ago
the mass of one hydrogen atom is 1.67x10^-27 kg. A cylinder contains 3.01x10^23 hydrogen atoms. What is the mass of the hydrogen
VladimirAG [237]
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5 0
3 years ago
What is the change in internal energy (ΔΕ) of a system when 5 kJ of work is done on the system while it releases 13 kJ of energy
meriva

The change in internal energy (ΔΕ) of a system : -8 kJ

<h3>Further explanation  </h3>

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created  

The equation is:  

 \tt \Delta U=Q+W

Energy owned by the system is expressed as internal energy (U)  

This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)  

The sign rules for heat and work are set as follows:  

• The system receives heat, Q +  

• The system releases heat, Q -  

• The system does work, W -  

• the system accepts work, W +  

5 kJ of work is done on the system : W = +5 kJ

releases 13 kJ of energy to the surroundings : Q = -13 kJ

\tt \Delta E=-13+5=-8~kJ

6 0
3 years ago
John is carefully pouring a chemical into a beaker when the beaker slips and breaks
Kryger [21]

Following laboratory safety protocols such as wearing personal protective equipment will protect John when the accident occurred.

<h3>What are laboratory safety protocols?</h3>

Laboratory safety protocols are the protocols put in place to ensure safety in the laboratory.

Laboratory safety protocols include the following:

  • always wear personal protective equipment in the laboratory
  • do not play in the laboratory
  • do not eat in the laboratory

Following laboratory safety protocols will help protect us from accidents which occur in the laboratory.

What happened when john was carefully pouring a chemical into a beaker when the beaker slips and breaks is an example of laboratory accident.

Wearing personal protective equipment will protect John.

In conclusion, following laboratory safety protocols will protect us when accidents occur in the laboratory.

Learn more about laboratory safety protocols at: brainly.com/question/17994387

#SPJ1

Note that the complete question is given as follows:

John is carefully pouring a chemical into a beaker when the beaker slips and breaks. How would laboratory safety protocols help John?

5 0
1 year ago
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