Question

Please please help me solve this, I have a test and only 20 mins left T-T​

Answer 1

Answer: $5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.Explanation:The balanced chemical equation is: [tex]2NH_4NO_3(s)\rightarrow 2MgO(s)+4NO_2(g)+O_2(g)$

According to stoichiometry :

2 moles of $NH_4NO_3$ produce = 4 moles of $NO_2$ gas and 1 mole of $O_2$ gas

2 moles of $NH_4NO_3$ produce = 5 moles of gas

Thus 0.1 mole of $NH_4NO_3$ produce =$\frac{5}{2}\times 0.1=0.25moles$  of gas

Volume of gas produced = $moles\times {\text {Molar volume}}=0.25moles\times 22.4dm^3/mol=5.6dm^3$

Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.