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Kitty [74]
2 years ago
13

Please please help me solve this, I have a test and only 20 mins left T-T​

Chemistry
1 answer:
Ann [662]2 years ago
7 0

Answer: 5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.Explanation:The balanced chemical equation is:
[tex]2NH_4NO_3(s)\rightarrow 2MgO(s)+4NO_2(g)+O_2(g)

According to stoichiometry :

2 moles of NH_4NO_3 produce = 4 moles of NO_2 gas and 1 mole of O_2 gas

2 moles of NH_4NO_3 produce = 5 moles of gas

Thus 0.1 mole of NH_4NO_3 produce =\frac{5}{2}\times 0.1=0.25moles  of gas

Volume of gas produced = moles\times {\text {Molar volume}}=0.25moles\times 22.4dm^3/mol=5.6dm^3

Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.

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<u>Explanation:</u>

Balancing the equation means, the number of atoms on both sides of the equation must be the same.

In the case of the given equation, we have to find out whether it is balanced or not.

2NH₂ + O₂ →  N₂ + 2H₂O

Atoms       Number of atoms before balancing     after balancing

                 LHS                 RHS                                    LHS         RHS

N               1                        2                                            2              2

H               2                       2                                            4              4                        

O               2                       1                                            2                2

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moles = mass/molar mass

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= 1000g/12gmol⁻¹

= 83.33 mol

now using the ideal gas equation

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a)

Here we calculate the mass of air over 1 square meter of surface.

Remember that atmospheric pressure is the consequence of the force exerted by all the air above the surface; 1 bar is equivalent to 1.020×10⁴kgm⁻²

NOW

mass of air = 1.020×10⁴kgm⁻² × 1m²

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Number of years = 1.65 years

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