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a_sh-v [17]
3 years ago
11

What is the solution to this equation?

Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Given

2(5x + 8) = 6x + 20 ← distribute parenthesis on left side

10x + 16 = 6x + 20 ( subtract 6x from both sides )

4x + 16 = 20 ( subtract 16 from both sides )

4x = 4 ( divide both sides by 4 )

x = 1 → B

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Mamont248 [21]
6/56 = 3/28........................
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3 years ago
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Which equations for the line of best fit do not accurately represent the data in the scatter plot? Select all that apply.
Inessa [10]

Concluding, the equations that do not accurately represent the data in the scatter plot are B, C, and D.

<h3></h3><h3>Which equations do not accurately represent the data in the scatter plot?</h3>

By looking at the scatter plot, we can see that as we read from left to right, the number of shoes sold (y variable) decreases.

Then the linear fit must have a negative slope, from that, we can discard options B and C.

Now, we also can see that the line starts almost at y = 70.

If you look at the option D, you can see that the constant term of that line is -70, so we can also discard that option.

Concluding, the equations that do not accurately represent the data in the scatter plot are B, C, and D.

If you want to learn more about scatter plots:

brainly.com/question/6592115

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8 0
9 months ago
PLEASE HELP 50 POINTS 100 students who are in 10th or 11th grade were asked if they participated in at least one extracurricular
Marina86 [1]

There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories. 

The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.

18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities. 

32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.

The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.

5 0
3 years ago
Consider the quadratic function f(x) = –2x2 + 4x – 2. Find the y-intercept and the equation of the axis of symmetry.
RoseWind [281]

Answer:

The y-intercept is -2

The equation of the axis of symmetry is x = 1 ⇒ 3rd answer

Step-by-step explanation:

* Lets revise the general form of the quadratic function

- The general form of the quadratic function is f(x) = ax² + bx + c,

 where a, b , c are constant

# a is the coefficient of x²

# b is the coefficient of x

# c is the y-intercept

- The meaning of y-intercept is the graph of the function intersects

 the y-axis at point (0 , c)

- The axis of symmetry of the function is a vertical line

  (parallel to the y-axis) and passing through the vertex of the curve

- We can find the vertex (h , k) of the curve from a and b, where

 h is the x-coordinate of the vertex and k is the y-coordinate of it

# h = -b/a and k = f(h)

- The equation of any vertical line is x = constant

- The axis of symmetry of the quadratic function passing through

  the vertex then its equation is x = h

* Now lets solve the problem

∵ f(x) = -2x² + 4x - 2

∴ a = -2 , b = 4 , c = -2

∵ The y-intercept is c

∴ The y-intercept is -2

∵ h = -b/2a

∴ h = -4/2(-2) = -4/-4 = 1

∴ The equation of the axis of symmetry is x = 1

4 0
2 years ago
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harina [27]

Answer:

the total weight of the hosepipe and the reel is 7.4 kg

Step-by-step explanation:

First, we need to find the weight of the hosepipe, we know that 1/2 metre of the hosepipe has a weight of 150 grams, therefore we can conclude that 1 meter has a weight of (150)(2) = 300 grams.

If one meter weighs 300 grams, then 20 meters have a weight of 20(300) = 6000 grams. But since 1000 grams are 1 kg, this would be equivalent to 6 kg.

Now, to find the total weight of the hosepipe and the reel we are going to sum up the 2 weights:

Total weight = hose pipe weight + reel weight

Total weight = 6 kg + 1.4 kg

Total weight = 7.4 kg.

Therefore, the total weight of the hosepipe and the reel is 7.4 kg

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