We want to see underline the correct part in each statement.
- 1) This situation illustrates (direct, <u>inverse</u>) variation.
- 2) The two quantities that must vary in this situation are (<u>weight and
</u>
- <u>distance from the cente</u><u>r</u>, height and weight).
- 3) The heavier the kid, the (<u>closer</u>, farther) he/she should be at the
- center to balance the seesaw?
- 4) When Jean moves farther from the center, Jericho tends to go (up,
- <u>down</u>).
- 5) If Jericho moves closer to the center, Jean tends to go (up, <u>down</u>).
So, Jean and Jericho are playing on a seesaw.
Jean is heavier than Jericho.
Now, notice that a seesaw is a lever. So it "amplificates" the force that you apply in one end to lift the weight that is on the other end. Depending on the form of the lever and the weights, the force that you need to do changes.
If we define:
- W₁ = Jean's weight.
- d₁ = Jean's distance to the center.
- W₂ = Jericho's weight.
- d₂ = Jericho's distance to the center.
We must have:
W₁*d₁ = W₂*d₂
Then:
1) This situation illustrates (direct, <u>inverse</u>) variation.
d₁, the position of Jean, varies inversely with respect to Jean's weight.
2) The two quantities that must vary in this situation are (<u>weight and
</u>
<u>distance from the center</u>, height and weight).
(by the equation above)
3) The heavier the kid, the (<u>closer</u>, farther) he/she should be at the
center to balance the seesaw?
By the given equation, we see that d₁ must be smaller than d₂.
And the last two are trivial:
4) When Jean moves farther from the center, Jericho tends to go (up,
<u>down</u>).
5) If Jericho moves closer to the center, Jean tends to go (up, <u>down</u>).
If you want to learn more, you can read:
brainly.com/question/18320907
