What is the answer to this question?

Mathematics

1 answer:

WARRIOR [948]3 years ago

3 0

Answer: Lower right corner

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Explanation:

The information that the temperature rises 3 degrees per hour will tell us the slope here. The slope is rise/run = 3/1 = 3. Each time we move up 3 on the y axis, we move 1 spot to the right.

As you can see in the bottom right hand corner graph, we start off at a temperature of 20 degrees. This is the point (x,y) = (0,20)

Then one hour later (x = 1), the temperature y bumps up to y = 23. Another hour passes by (x = 2) and y becomes y = 26. And so on.

You might be interested in

Substitute the value n = 4 in the expressions 2n n + 2 3(n+4)

Lelu [443]

Step-by-step explanation:

Given n = 4

2n = 2* 4= 8

n + 2 = 4 + 2 = 6

3(n + 4) = 3( 4 + 4) = 3 * 8 = 24

Hope it will help :)

4 0

3 years ago

1. M is the midpoint of LN and O is the midpoint of NP.

Reptile [31]

1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4.
The line would be
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5.
a. Circumcenter: the intersection of perpendicular bisector lines
b. Incenter: the intersection of bisector lines
c. Centroid: the intersection of median lines
d. Orthocenter: the intersection of altitude lines

5 0

3 years ago

Evaluate the triple integral_E x^6e^y dV where E is bounded by the parabolic cylinder z = 25 - y^2 and the planes z = 0, x = 5,

Nimfa-mama [501]

Nothing crazy here, just a matter of figuring out the limits of integration.

$\displaystyle\iiint_Ex^6e^y\,\mathrm dV=\int_{-5}^5\int_{-5}^5\int_0^{25-y^2}x^6e^y\,\mathrm dz\,\mathrm dy\,\mathrm dx$