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Schach [20]
3 years ago
10

Donavon and three friends go to a fair. They each spend 1/2 of their money on rides. Then, they each spend $3 on food. At the en

d of the day, Donavon and his friends have a total of $8 remaining. How much money did each person bring to the fair?

Mathematics
1 answer:
Ghella [55]3 years ago
6 0
X=22$ hopefully this helpssss

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Evaluate 14+(-9)+(-9)
Vilka [71]
The answer to your question is -4
6 0
3 years ago
Express 24 as a fraction of 60
seraphim [82]

Answer:

24/60 = 2/5

Step-by-step explanation:

24/60

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4/10

Divide both the numerator and denominator by a common factor, 2

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7 0
3 years ago
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I need help with this homework can anyone help me. I need work too, help is appreciated:)
quester [9]
Let x = # of tickets sold in advance 
Let y = # of tickets sold the day of 


Cost of the tickets & total sales: 6x & 10y = 6828

You also know y = x + 206

Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828

Now solve for x to get x = 298

To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.

So, 298 tickets were sold in advance and 504 tickets were sold the day of
3 0
3 years ago
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What is the answer I will need help
Hoochie [10]
Answer D, 4 sets of -3 jumps to reach -12
5 0
2 years ago
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if you actually know plz give an explanation to the answer so i know you aren't just answering for points, please help this is d
Kaylis [27]

Answer:

B

Step-by-step explanation:

Probability of getting 9 or 11 = 2 /6 =1/3

Probability of getting tails in coin = 1/ 2

Probability of getting  9 or 11 AND tails in coin toss = 1/2 * 1/3

= 1/6

4 0
3 years ago
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