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bixtya [17]
4 years ago
8

What is 25x^2 above 5x

Mathematics
1 answer:
netineya [11]4 years ago
6 0

Answer:

\frac{25 {x}^{2} }{5x}   \\ =  \frac{5 \times 5 \times x \times x}{5 \times x}  \\  = 5x

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What are the solutions of the equation x4 95x2 â€"" 500 = 0? Use factoring to solve.
liq [111]

All the values of the <em>x</em> <em> </em>for the given function are \sqrt{5},-\sqrt{5}, 10i and -10i.

Given-

Given function is,

x^{4}+95x^2-500=0

Rewrite the equation,

(x^2)^2+95x^2-500=0

Let <em>u </em>in place of x^2 and rewrite the equation in the form of u,

u^2+95u-500=0

Break the 95 in factors and rewrite the equation,

u^2+100u-5u-500=0

u(u+100)-5(u+100)=0

(u+100)(u-5)=0

Replace the value of u with x^2,

(x^2+100)(x^2-5)=0

It is known that If any individual factor on the left side of the equation is equal to zero then the entire expression will be equal to zero. therefore we get,

x^2-5=0

further, solve it,

x^2=5

x=\sqrt{5},-\sqrt{5}

And another factor is

x^2+100=0

x^2=-100

x=10i,-10i

Hence, all the values of the <em>x </em>for the given function are \sqrt{5},-\sqrt{5},  10i , and  -10i.

For more about the factorization, follow the link below-

brainly.com/question/6810544

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3x + 2y = 19
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