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3 years ago

What is the range of the given function?

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

The range is the set of y values of a function or relation. In this case, it's the set {9, 0, -7, -1}. The order of the items in the set doesn't matter. We can rearrange that to get {-7, -1, 0, 9}

This is why the answer is choice B

leonid [27]3 years ago

6 0

Answer:

Step-by-step explanation:

The answer is B

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2/18 +15/18 =17/18?

NeX [460]

Answer:

17/18

Step-by-step explanation:

2 /18 + 15 /18

= 2 /18 + 15/ 18

= 2+15 /18

= 17 /18

4 0

3 years ago

Find an equation for the nth term of the arithmetic sequence. -15, -6, 3, 12, ...

Mariulka [41]

Answer: $t_{n}=-15+9(n-1)$

Step-by-step explanation:

The formula for finding the nth term of an arithmetic sequence is given as:

$t_{n}=a+(n-1)d$

$a =$ first term = -15

$d =$ common difference = -6 - (-15) = 9

$n =$ number of terms

substituting into the formula , we have :

$t_{n} = -15+(n-1)9$

$t_{n}=-15+9(n-1)$

5 0

3 years ago

In the above bridge, line segment BD is the perpendicular bisector of line segment AC. For the bridge to be safe, Triangle ABD i

klasskru [66]

Answer: we can get the sequence of reasons with help of below explanation.

Step-by-step explanation:

Here It is given that, line segment BD is the perpendicular bisector of line segment AC. ( shown in below diagram)

By joining points B with A and B with C ( Construction)

We get two triangles ABD and CBD.

We have to prove that : Δ ABD ≅ Δ CBD

Statement Reason

1. AD ≅ DC 1. By the property of segment bisector

2. ∠BDA ≅ ∠ BDC 2. Right angles

3. BD ≅ BD 3. Reflexive

4. Δ ABD ≅ Δ CBD 4. By SAS postulate of congruence

8 0

4 years ago

At a company picnic, 1/2 of the people are employees. 2/5 are employees' spouses. What percent are neither?

kupik [55]

Answer:

10% of the people at the picnic are neither.

Step-by-step explanation:

To get the answer,

1/2 + 2/5 = 9/10

10/10 - 9/10 = 1/10

1/10 = 10%

Thanks, I hope I got this right!

7 0

3 years ago

Find the equation of the parabola that passes through

valentinak56 [21]

so we have the points of (0,-7),(7,-14),(-3,-19), let's plug those in the y = ax² + bx + c form, since we have three points, we'll plug each one once, thus a system of three variables, and then we'll solve it by substitution.

$\bf \begin{array}{cccllll} \stackrel{\textit{point (0,-7)}}{-7=a(0)^2+b(0)+c}& \stackrel{point (7,-14)}{-14=a(7)^2+b(7)+c}& \stackrel{point (-3,-19)}{-19=a(-3)^2+b(-3)+c}\\\\ -7=c&-14=49a+7b+c&-19=9a-3b+c \end{array}$

well, from the 1st equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".

$\bf -14=49a+7b-7\implies -7=49a+7b\implies -7-49a=7b \\\\\\ \cfrac{-7-49a}{7}=b\implies \cfrac{-7}{7}-\cfrac{49a}{7}=b\implies -1-7a=b$

well, now let's plug that "b" into our 3rd equation and solve for "a".

$\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill$

3 0

4 years ago