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weqwewe [10]
2 years ago
13

2(x+3)/x(x-1) times 4x(x+2)/10(x+3)

Mathematics
1 answer:
Feliz [49]2 years ago
5 0

Answer:

this may be correct answer .and sorry if it is wrong

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Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.
dalvyx [7]

Answer:

Step-by-step explanation:

your equation shown above is set up incorrectly in order to solve this i need the right equation you must plug in each number to q to find the right solution

4 0
3 years ago
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(2x+4)^2 - (x-5)^2 = 26x<br> Please solve (explained)
Zina [86]

Expand the squared binomials:

(2x+4)^2=4x^2+16x+16

(x-5)^2=x^2-10x+25

Then

(4x^2+16x+16)-(x^2-10x+25)=3x^2+26x-9=26x

\implies3x^2-9=0

\implies3x^2=9

\implies x^2=3

\implies x=\pm\sqrt3

5 0
3 years ago
If the volume of the pyramid shown is 360 inches cubed, what is its height?
dimaraw [331]

Answer:

9 inches

Step-by-step explanation:

The formula for the volume of a rectangular pyramid is V = \frac{1}{3}(l*w*h)

  • Here we have volume (V), base (L), and width (W)
  • V = 360 in³, L = 12 in, W = 10 in

We need to manipulate the volume equation to solve for the height (H)

  • First we need to multiply both sides by 3 to get rid of the fraction:  3V = L×W×H
  • Then we need to divide both sides by (L×W) to get: \frac{3V}{lw} =h

Now we can plug in the given values:

  • \frac{3(360in^{3}) }{(12 in)(10in)} =\frac{1080in^{3} }{120in^{2} } = 9in
  • The height is 9 inches
4 0
3 years ago
Identify the equation of the graph shown. A) y = 2x + 3 B) y = 2x - 3 C) y = -2x + 3 D) y = -2x - 3 4)
Anna35 [415]

Answer:

The answers provided aren't reasonable for this graph.

Step-by-step explanation:

The graph's y-intercept is -2, since that is the point where the line intersects the y-axis. The slope is 3x, because the distance from one point to the next is 3 up, 1 right. So the equation for the graph is y = 3x - 2.

4 0
2 years ago
Find the area of following figure...?​
MrRa [10]

Answer:

33600 m²

Step-by-step explanation:

The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.

area of trapezoid = (a + b)h/2

where a and b are the lengths of the bases, and h is the height.

We need to find the height, BC.

Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.

DE + EC = DC

EC = AB = 360 m

DC = 600 m

DE + 360 m = 600 m

DE = 240 m

Use right triangle ADE to find AE. Then BC = AE.

DE² + AE² = AD²

DE² + 240² = 250²

DE² = 62500 - 57600

DE² = 4900

DE = √4900

DE = 70

BC = 70 = h

area = (a + b)h/2

area = (600 m + 360 m)(70 m)/2

area = 33600 m²

4 0
1 year ago
Read 2 more answers
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