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3 years ago

What is the price called at which the quantity demanded is equal to the quantity supplied?

Mathematics

2 answers:

sladkih [1.3K]3 years ago

8 0

Equilibrium Price
Hope This Helps

Simora [160]3 years ago

8 0

Equilibrium Price would be your answer.
I hope this helps.

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PLS ANSWER BOTH PARTS I WILL GIVE BRAINLIEST PLSSS HURRRYYYY

sertanlavr [38]

Answer: slope is 1/3

Step-by-step explanation: make a graph of y=1/3x+9

7 0

1 year ago

Find the radical equivalent of 27^2/3 and compute it.<br> please help i'm taking a test.

AveGali [126]

Note that (a^b)^c=a^(bc) so in this case we have:

(27^(1/3))^2 the cube root of 27=±3

(±3)^2 and ±3^2=9

So the equivalent expression is 9 or if you need an exponent 9^1 :)

I am assuming that you meant 27^(2/3)

6 0

3 years ago

Read 2 more answers

In French how would you conjugate verbs with "on"?

mafiozo [28]

You conjugate verbs with the pronoun 'on' the same way you conjugate verbs with pronouns 'il/elle'. "On" means "one", qs in "One can do x or y."

4 0

3 years ago

Four people are carpeting a house. Heidi carpets 16 of the house, Lisa carpets 16% of the house, Martina carpets 0.2 of the hous

Alborosie

Answer:

Heidi, Lisa, Jaydie, and Martina

Step-by-step explanation:

16%, 16%, 18%, 20%

5 0

3 years ago

Big babies: The National Health Statistics Reports described a study in which a sample of 354 one-year-old baby boys were weighe

Vedmedyk [2.9K]

Answer:

Yes. The data provide enough evidence to support the claim that the mean weight of one-year-old boys is greater than 25 pounds.

P-value=P(t>2.84)=0.0024

Step-by-step explanation:

Hypothesis test on the population mean.

The claim is that the mean weight of one-year-old boys is greater than 25 pounds.

Then, the null and alternative hypothesis are:

$H_0: \mu=25\\\\H_a:\mu>25$

The significance level is α=0.05.

The sample size is n=354. The sample mean is 25.8 pounds and the sample standard deviation is 5.3 pounds. As the population standard deviation is estimated from the sample standard deviation, we will use a t-statistic.

The degrees of freedom are:

$df=n-1=354-1=353$

The t-statistic is:

$t=\dfrac{\bar x-\mu}{s/\sqrt{n}}=\dfrac{25.8-25}{5.3/\sqrt{354}}=\dfrac{0.8}{0.2817}=2.84$

For a right tailed test and 353 degrees of freedom, the P-value is:

$P-value=P(t>2.84)=0.0024$

As the P-value is smaller than the significance level, the effect is significant and the null hypothesis is rejected.

There is enough evidence to support the claim that the mean weight of one-year-old boys is greater than 25 pounds.

7 0

2 years ago