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AveGali [126]
3 years ago
5

For the sequence an 4n + 7, which term number is 335?

Mathematics
1 answer:
Kitty [74]3 years ago
8 0
N equal 175 thanks me later
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What are the zeros of this polynomial and state their multiplicity at each <br> y=(x-5)(x+2)^2
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Answer:

C.

Step-by-step explanation:

The zeros of a polynomial are the x-intercepts of the function. To find them, we factor the polynomial and set each factor equal to 0.

This polynomial is already factored so set each to 0 and solve for x.

x-5=0\\x=5\\(x+2)^{2}=0 \\(x+2)=0\\x=-2

This means x=-2, 5. Each zero or root has a multiplicity - the number of times the factor occurs. This is also known as the exponent of the factor expression.

(x+5) occurs once since it has exponent 1.

(x+2)^{2} occurs twoce since it has exponent 2.

x=5 mult. 1, x=-2 mult. 2



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