Https://photomath.net/s/P56lb

The link will show you how to solve the problem but if you still don't get it you download the app Photomath and it will give you more detailed steps.

8 0

3 years ago

The football game at davison high school started at 7:05 p.m . the game ended at 9:43 p.m. .how long did the game last

Ivanshal [37]

2 hours and 38 minutes.
Hope this Helps! :)

7 0

3 years ago

Please help with geometry homework will make brainliest

o-na [289]

<u>Answer</u>

<u>Explanation</u>

The two lines in the diagram are secants meeting outside the circle.

The products of a secant and the extension of the chord of one line is equal to the products of a secant and the extension of the chord of the other line.

∴ 4 × 9 = x × 12

36 = 12x

x = 36/12

= 3

4 0

2 years ago

Please Help Me

ludmilkaskok [199]

Given:

The point (9,-12) is on terminal side of angle theta in standard position.

To find:

The exact value of each of the six trigonometric functions of theta.

Solution:

The given point is (9,-12). Here, x-coordinate is positive and y-coordinate is negative. So, the point lies in 4th quadrant and only cos and sec are positive in 4th quadrant.

We know that,

$r=\sqrt{x^2+y^2}$

$r=\sqrt{9^2+(-12)^2}$

$r=\sqrt{81+144}$

$r=\sqrt{225}$

$r=15$

Now,

$\sin \theta=\dfrac{y}{r}=\dfrac{-12}{15}=-\dfrac{4}{5}$

$\cos \theta=\dfrac{x}{r}=\dfrac{9}{15}=\dfrac{3}{5}$

$\tan \theta=\dfrac{y}{x}=\dfrac{-12}{9}=-\dfrac{4}{3}$

$\cot \theta=\dfrac{1}{\tan \theta}=-\dfrac{3}{4}$

$\text{cosec} \theta=\dfrac{1}{\sin \theta}=-\dfrac{5}{4}$

$\sec \theta=\dfrac{1}{\cos \theta}=\dfrac{5}{3}$

Therefore, the values of six trigonometric functions of theta are $\sin \theta=-\dfrac{4}{5},\cos \theta=\dfrac{3}{5},\tan \theta=-\dfrac{4}{3},\cot \theta=-\dfrac{3}{4},\text{cosec} \theta=-\dfrac{5}{4},\sec \theta=\dfrac{5}{3}$ .

6 0

3 years ago