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love history [14]

4 years ago

7

9. WHERE SHOULD YOU START MAKING A U-TURN WHEN DRIVING ON A DIVIDED STREET WITH MULTIPLE LANES IN YOUR DIRECTION? A. On the shou

lder B. In the left lane C. In the median

2 answers:

Snowcat [4.5K]4 years ago

6 0

I believe the answer is in the left lane

Dmitriy789 [7]4 years ago

3 0

100% B! (in the left lane)

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What distance will a vehicle travel before coming to a complete stop from a speed of 70 mph, (a) When the vehicle is traveling o

OLga [1]

Answer:

(a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be $723.91>SSD>620.2$

(c), The SSD will be 910.5 ft.

Explanation:

Given that,

Speed = 70 mph

Suppose, a perception reaction time of 2.5 sec and the coefficient of friction is 0.35

We need to calculate the stopping sight distance

Using formula of SSD

$SSD=1.47\times v\times t+\dfrac{v^2}{30\times(f\pm g)}$

Where, v = speed of vehicle

t = perception reaction time

f = coefficient of friction

g = gradient of road

(a). If the gradient of road is zero.

Then, the stopping sight distance will be

$SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35)}$

$SSD=723.9\ ft$

(b-1). If the gradient of road is 0.1

Then, the stopping sight distance will be

$SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35+0.1)}$

$SSD=620.2\ ft$

(b-2). If the grade continuously decrease then the SSD will be increase.

But if the grade is increase then the SSD will be decrease and for flat grade the SSD will be more.

So, The SSD will be $723.91>SSD>620.2$

(c). When the vehicle is traveling downhill on a roadway of constant grade then the vehicle take will be more SSD

So, The SSD will be

$SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35-0.1)}$

$SSD=910.5\ ft$

Hence, (a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be $723.91>SSD>620.2$

(c), The SSD will be 910.5 ft.

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4 years ago

8. A boy pulls a 20.0-kg box with a 140-N force at 30° above a horizontal surface. If the coefficient of kinetic friction betwee

LenaWriter [7]

0.280 m is the correct answer

8 0

3 years ago

WRONG ANSWERS WILL BE REPORTED

Dmitry_Shevchenko [17]

The answer to number 9 is C, decreased muscle tension. I believe number 10 is D, prepares an organism to respond to stress.

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3 years ago

A spring with k = 53 N/m hangs vertically next to a ruler. The end of the spring is next to the 18 cm mark on the ruler. If a 2.

Anarel [89]

Answer:

1.07 m

Explanation:

x = Compression of the spring

k = Spring constant = 53 N/m

Initial length = 18 cm

P = Kinetic energy

K = Kinetic energy

At the lowest point of the mass the energy conservation is as follows

$P_{ig}+P_{is}+K_i=P_{fg}+P_{fs}+K_f\\\Rightarrow mgx+0+0=mgx+\frac{1}{2}kx^2\\\Rightarrow x=\frac{2mg}{k}\\\Rightarrow x=\frac{2\times 2.4\times 9.81}{53}\\\Rightarrow x=0.89\ m$

At its lowest position the mark on the ruler will be

$x_f=0.18+0.89\\\Rightarrow x_f=1.07\ m$

The spring line will end up at 1.07 m

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3 years ago

Anger is to angry as fire is to what

finlep [7]

<span>Anger is to angry as fire is to blazing. </span>

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3 years ago