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skelet666 [1.2K]
3 years ago
10

When carrying extra weight, the space formed between the top of your head and the two axles of the motorcycle is referred to as

the?
Physics
1 answer:
Dafna11 [192]3 years ago
3 0
When carrying extra weight, the space formed between the top of your head and the two axles of the motorcycle is called "load triangle". Because of a motorcycle's size and weight<span> and the fact that it has only two wheels, how to carry extra load is very important. One has to make sure that they are keeping the weight low and close to the middle of the motorcycle and keep the load evenly from side to side. Heavier items should be in the "load triangle".</span><span> </span>
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How much heat is released when 12.0 grams of helium gas condense at 2.17 K? The latent heat of vaporization of helium is 21 J/g.
uranmaximum [27]
To determine the heat released by the process of condensation, we simply multiply the amount of the gas that condensed to the latent heat of vaporization. We do as follows:

Heat released = 21 J/g (12.0 g ) = 252 J of heat released
8 0
3 years ago
Read 2 more answers
9. In the sun devil football game, a receiver, who is standing still, has caught a pass from the quarterback. Before he can move
otez555 [7]

Answer:

The mass of the receiver is 68.862 kg

Explanation:

Given;

let mass of the receiver be "m₁"

initial velocity of the receiver, u₁ = 0

mass of the tackler, m₂ =  156 kg

initial velocity of the tackler, u₂ = 6.89 m/s

their final velocity, v = 4.78 m/s

Apply the principle of conservation of linear momentum, for inelastic collision;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(m₁ x 0) + (156 x 6.89) = 4.78(m₁ + 156)

0 + 1074.84 = 4.78 (m₁ + 156)

1074.84 = 4.78 (m₁ + 156)

m₁ + 156 = 1074.84 / 4.78

m₁ + 156 = 224.862

m₁ = 224.862 - 156

m₁ = 68.862 kg

Therefore, the mass of the receiver is 68.862 kg

5 0
3 years ago
An electron with a charge value of 1.6x10^-19 C is in the presence of an electric field of 300 N/C when located between a pair o
Blababa [14]

(1.6 x 10⁻¹⁹ C) x (300 N/C) = <em>4.8 x 10⁻¹⁷ Newton</em>

<em></em>

6 0
4 years ago
Starting fom rest, a car accelerates at a constant rate, reaching 88 km/h in 12 s. (a) What is its acceleration? (b) How far doe
JulsSmile [24]

Answer:

(A)  a=2.0.37m/sec^2

(B) s = 146.664 m

Explanation:

We have given car starts from the rest so initial velocity u = 0 m /sec

Final velocity v = 88 km/hr

We know that 1 km = 1000 m

And 1 hour = 3600 sec

So 88km/hr=88\times \frac{1000}{3600}=24.444m/sec

Time is given t = 12 sec

(A) From first equation of motion v = u+at

So 24.444=0+a\times 12

a=2.0.37m/sec^2

So acceleration of the car will be a=2.0.37m/sec^2

(b) From third equation of motion v^2=u^2+2as

So 24.444^2=0^2+2\times 2.037\times s

s = 146.664 m

Distance traveled by the car in this interval will be 146.664 m

6 0
4 years ago
How do you convert 1.3*10^6cal into joules
ehidna [41]

Answer:

5.4×10⁶J

Explanation:

1 cal = 4.184 J

1.3×10⁶ cal × (4.184 J/cal) = 5.4×10⁶J

3 0
3 years ago
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