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3 years ago

If you ride your bicycle down a straight road for 500m then turn around and ride back, your distance is____ your displacement.

2 answers:

7 0

If you ride your bicycle down a straight road for 500m then turn around and ride back, your distance is greater than your displacement.

Answer: A

Explanation

Here, distance is the total measurement the rider drives from starting to the ending point and back from the ending point to the starting point.

It is given that the rider travels a straight road of 500 m.

The distance d1, in which rider starts from the starting point to the ending point is 500m.

The distance d2, in which rider starts from ending point back to the starting point is 500m. Therefore total distance= d1+d2=500+500= 1000m.

Displacement, the shortest distance from the initial (here starting point) to final (ends at starting point) position of the rider. Therefore the displacement, in this case, = 0m.

So distance-1000m>displacement-0m.

Helen [10]3 years ago

4 0

Answer:

C-less than

Explanation:

Distance is total distance traveled (1000m here if you stop where you started).

Displacement is your final distance from where you started (0m if you stop where you started).

0m<1000m

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3 years ago

Consult Interactive Solution 16.15 in order to review a model for solving this problem. To measure the acceleration due to gravi

morpeh [17]

Answer:

g = 1.19 m / s²

Explanation:

Let's solve this problem in parts.

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v = 1.52 / 0.0833

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8 0

3 years ago

NEED HELP

ch4aika [34]

Answer: C.

Explanation:

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3 years ago

A bike is traveling to the left with the speed of 27 m/s when the rider slams on the brakes. The bike skids for 41.5 m with the

Darina [25.2K]

The acceleration of the bike is equal to $8.78\frac{m}{s^{2}}$ opposing the movement (to the right).

Why?

Since after the rider slams the brakes, the bike came to a stop, we know that the acceleration is opposite to the velocity/movement.

We can use the following equation to calculate the acceleration:

$v_{f}^{2}=v_{o}^{2}+2*a*d$

So, substituting, we have: (let's consider negative to the left and positive to the right)

$0=(-27\frac{m}{s} )^{2}+2*a*41.5m\\\\0=729\frac{m^{2} }{s^{2} }+83*a\\\\a=\frac{-729\frac{m^{2}}{s^{2}}}{83m}=-8.78\frac{m}{s^{2}}$

The negative sign means that the acceleration's direction is opposite to the movement.

Hence, we have that the acceleration is equal to $8.78\frac{m}{s^{2}}$ opposing the movement (to the right).

Have a nice day!

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4 years ago

Read 2 more answers

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The oscillation of a body or system with its own natural frequency and under no external influence other than the impulse that initiated the motion. — called also free vibration. —opposed to forced oscillation.

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