Answer:
H = 1/2 g t^2 where t is time to fall a height H
H = 1/8 g T^2 where T is total time in air (2 t = T)
R = V T cos θ horizontal range
3/4 g T^2 = V T cos θ 6 H = R given in problem
cos θ = 3 g T / (4 V) (I)
Now t = V sin θ / g time for projectile to fall from max height
T = 2 V sin θ / g
T / V = 2 sin θ / g
cos θ = 3 g / 4 (T / V) from (I)
cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ
tan θ = 2/3
θ = 33.7 deg
As a check- let V = 100 m/s
Vx = 100 cos 33.7 = 83,2
Vy = 100 sin 33,7 = 55.5
T = 2 * 55.5 / 9.8 = 11.3 sec
H = 1/2 * 9.8 * (11.3 / 2)^2 = 156
R = 83.2 * 11.3 = 932
R / H = 932 / 156 = 5.97 6 within rounding
Answer:
D
Explanation:
This will not change the weight and therefore not change the inertia
The stone will take 2.89 seconds to hit the water.
The time required by the stone to hit the water is calculated by the second equaiton of motion
s=ut+
gt^2
41=0×t+×9.81×t²
t=2.89 seconds
Answer:
They can do this with the help of mechanical power generated from the human muscle.
Explanation:
Since rescue workers engage in missions where it is usually difficult for them to get electrical energy to their devices and working tools, they could employ various materials that can be sourced around them to get energy to their tools. One of such is the mechanical power generated from the human body through squeezing and compressing.
Some green devices such as the dyno torch have been designed to be powered through this method. Repeated squeezing of its flywheel allows light to be generated.
Answer:distance divided by time
Explanation:
