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eduard
3 years ago
8

Which of the following measurements contains two significant figures? A. 0.00300 L B. 0.00303 L C. 0.00033 L D. 0.00330 L

Chemistry
2 answers:
mr Goodwill [35]3 years ago
6 0

Answer:

C. 0.00033 L.

Explanation:

A. 0.00300 L:

It has 3 significant figures that are in bold (0.00300 L).

3 is a significant figure (Nos. from 1 to 9 are considered to be significant numbers).

Zeros to the right of (Nos. from 1 to 9) are countable as significant Nos. if there is a decimal point.

So, It has 3 significant figures.

<em>B. 0.00303 L:</em>

It has 3 significant figures that are in bold (0.00303 L).

3 is a significant figure (Nos. from 1 to 9 are considered to be significant numbers).

Zeros between (Nos. from 1 to 9) are countable as significant Nos.

So, It has 3 significant figures.

C. 0.00033 L:

It has 2 significant figures that are in bold (0.00033 L).

3 is a significant figure (Nos. from 1 to 9 are considered to be significant numbers).

Zeros to the left of (Nos. from 1 to 9) are not countable as significant Nos.

So, It has 2 significant figures.

D. 0.00330 L:

It has 3 significant figures that are in bold (0.00330 L).

3 is a significant figure (Nos. from 1 to 9 are considered to be significant numbers).

Zeros to the right of (Nos. from 1 to 9) are countable as significant Nos. if there is a decimal point.

So, It has 3 significant figures.

So, the right choice is: C. 0.00033 L.

Lisa [10]3 years ago
4 0

Answer:

c 0.00033 L

Explanation:

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Given that:

The argon atoms are excited into an excited state before emitting the 488.0 nm laser.

the energy of the first ionization energy of argon is 1520 kJ mol-1.

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Therefore, the energy of the first ionization energy of argon in eV is = ( 1520/ 96.49) eV

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To find where  the energy level of the excited state lies below the vacuum energy level, let's first determine, the energy liberated by using planck expression.

E = \dfrac{hc}{\lambda}

E  = \dfrac{6.6 \times 10^{-34} \times 3 \times 10^8}{488 \times 10^{-9}}

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E  = \dfrac{1.98 \times 10^{-25}}{488 \times 10^{-9}}

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