All categories

3 years ago

What is the diffrince in snow and hail?

1 answer:

7 0

The difference is snow is made up of one or more tiny ice crystals that come together to form a intricate and unwise shape of snowflakes and hail is a frozen raindrop and is generally a lot bigger than a pure crystal of ice

You might be interested in

25. The periodic table is based on an element's A. atomic number. B. molecular size. C. molecular mass. D. atomic mass.

VashaNatasha [74]

It is arranged by Atomic Number

8 0

3 years ago

Read 2 more answers

Gas is trapped within a container held at a constant temperature. If the volume of the

Citrus2011 [14]

The gas would diffuse as much as it could

6 0

3 years ago

Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).

12345 [234]

1) 385 J

2) 450 J

Explanation:

The amount of energy that must be absorbed by a certain substance in order to increase its temperature by $\Delta T$ is given by the equation:

$Q=mC\Delta T$

where

m is the mass of the substance

C is its specific heat capacity

$\Delta T$ is the increase in temperature of the substance

For the block of copper in this problem, we have:

m = 10 g is the mass

$C=0.385 J/gK$ is the specific heat capacity of copper

$\Delta T=400-300 = 100 K$ is the change in temperature

So, the energy absorbed by the block of copper is

$Q=(10)(0.385)(100)=385 J$

Similarly for the block of iron, the energy absorbed by the iron is given by

$Q=mC\Delta T$

where

m is the mass of the block of iron

C is its specific heat capacity of iron

$\Delta T$ is the increase in temperature of the block

Here we have:

m = 10 g is the mass of the block

$C=0.450 J/gK$ is the specific heat capacity of iron

$\Delta T=400-300 = 100 K$ is the change in temperature

So, the energy absorbed by the block of iron is

$Q=(10)(0.450)(100)=450 J$

6 0

3 years ago

How many molecules are in a drop of water weighing 0.05 g?

Scilla [17]

Answer:

0.05 g of H2O contain molecules

7 0

3 years ago

You are given stocks of 4 M NaCl, 40% Glucose, and 1M Tris-HCl (pH 8.5). You need to make 400 ml of a buffer containing 0.5 M Na

OLga [1]

Answer:

50mL of 4M NaCl, 80mL of 40% glucose, 20mL of 1M Tris-HCl (pH 8.5) and 250mL of water.

Explanation:

To make 400mL containing 0.5M NaCl you need to add:

4M / 0.5M = 8 (dilution 1/8). 400mL / 8 = 50 mL of 4M NaCl.

Glucose 8% you need to add:

40% / 8% = 5 (dilution 1/5). 400mL / 5 = 80 mL of 40% glucose 

Buffer 50mM you need to add:

1000mM / 50mM = 20 (dilution 1/20). 400mL / 20 = 20mL of 1M Tris-HCl (pH 8.5)

The resting volume: 400mL - 50mL of 4M NaCl - 80mL of 40% glucose - 20mL of 1M Tris-HCl (pH 8.5) = 250 mL must be completed with water.

Thus, to make the solution you need: 50mL of 4M NaCl, 80mL of 40% glucose, 20mL of 1M Tris-HCl (pH 8.5) and 250mL of water.

I hope it helps!

8 0

3 years ago