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3 years ago

Solve pls brainliest

Mathematics

2 answers:

umka2103 [35]3 years ago

7 0

Answer:

A would be 9 and I am not sure about B.

Step-by-step explanation:

when a number is in | | these lines then they will always come out positive.

Andreyy893 years ago

3 0

Answer:

1. 9

2. 5

Step-by-step explanation:

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Please help me answers, don’t give links pls

Misha Larkins [42]

Answer:

Step-by-step explanation:

7 0

3 years ago

Please explain how you found the answer.

otez555 [7]

35 divided by 5 = 7
7 x 2 = 14
So c) 14

And I have no idea about the second one sorry :/

8 0

3 years ago

Read 2 more answers

PLEASE HELP IMMEDIATELY

grandymaker [24]

Answer:

a) C(d) = 37.95 + 0.62d

b) C(74) = 37.95 + 0.62(74)

83.8 dollars

c) 8181 miles

Step-by-step explanation:

The company charges a fee of 37.95 just for the rent and then 0.62 dollars per mile.

So if one person travels one mile they will pay:

37.95 + 0.62

Two miles: 37.95 + 0.62 (2)

Three miles: 37.95 + 0.62 (3)

d miles: 37.95 + 0.62(d)

Thus, the function C(d) that gives the total cost of renting the truck for one day if you drive d miles would be C(d) = 37.95 + 0.62d

Now, if we drive 74 miles, the function that gives us the cost would be:

C(74) = 37.95 + 0.62(74) = 37.95 + 45.88 = 83.83 = 83.8 dollars

Now, if we have 5110 dollars on our budget, we would have to substitute this in our function to know how many miles we can drive with that amount:

$C(d)= 37.95+0.62d=5110\\37.95+0.62d=5110\\0.62d=5110-37.95\\0.62d=5072.05\\d=5072.05/ 0.62 \\d=8180.7$

Thus, we could drive 8181 miles

3 0

3 years ago

How many permutations can be formed from all the letters in the word engineering?

laila [671]

Answer:

277,200

Step-by-step explanation:

To find the number of permutation we can form from the letters of the word "engineering", we first need to find the frequencies of the different letters present.

E = 3

G = 2

N= 3

I = 2

R = 1

Now that we have the frequencies, we count the number of letters in the word "engineering".

E N G I N E E R I N G

11 letters

Now we take the factorial of total number of letters and divide it by the number of repeats and their factorial

So we get:

$\dfrac{11!}{3!2!3!2!1!}$

We remove the 1! because it will just yield 1.

$\dfrac{11!}{3!2!3!2!}$

So the total number of permutations from the letters of the word "engineering" will be:

Total number of permutations = $\dfrac{39,916,800}{144}$

Total number of permutations = 277,200

3 0

4 years ago

Substitution to evaluate the indefinite integral

gregori [183]

Answer:

$\displaystyle \int {e^{5x}} \, dx = \boxed{ \frac{e^{5x}}{5} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {e^{5x}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u:
$\displaystyle u = 5x$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = 5 \ dx$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \begin{aligned}\int {e^{5x}} \, dx & = \frac{1}{5} \int {5e^{5x}} \, dx \\\end{aligned}$
[Integral] Apply Integration Method [U-Substitution]:
$\displaystyle \begin{aligned}\int {e^{5x}} \, dx & = \frac{1}{5} \int {5e^{5x}} \, dx \\& = \frac{1}{5} \int {e^u} \, du \\\end{aligned}$
[Integral] Apply Exponential Integration:
$\displaystyle \begin{aligned}\int {e^{5x}} \, dx & = \frac{1}{5} \int {5e^{5x}} \, dx \\& = \frac{1}{5} \int {e^u} \, du \\& = \frac{e^u}{5} + C \\\end{aligned}$
[u] Back-substitute:
$\displaystyle \begin{aligned}\int {e^{5x}} \, dx & = \frac{1}{5} \int {5e^{5x}} \, dx \\& = \frac{1}{5} \int {e^u} \, du \\& = \frac{e^u}{5} + C \\& = \boxed{ \frac{e^{5x}}{5} + C } \\\end{aligned}$

∴ we have used substitution to evaluate the indefinite integral.

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Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27593180

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

3 0

2 years ago