Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3
Note: Negative time (-0.2) is not valid
#25.
Convert the fractional numbers into decimals for easier comparison.
3 2/3 is approximately 3.66
-4 2/5 is approximately -4.4
We now have: 3, 3.66, -4.2, -4.4
In order: -4 2/5, -4.2, 3, 3 2/3
#26.
All positive numbers are greater than negative numbers.
When comparing two negative numbers, the one with the larger absolute value, will be less.
So (G) is correct
#27.
25 = m + 6.3
25 - 6.3 = m + 6.3 - 6.3
m = 18.7
#28.
h = 3.2-1.6 = 1.6
#29.
x = 15.6 - 9.8 = 5.8
#30
p = 17 - 4.5 = 12.5
Answer:
7
Step-by-step explanation:
Remark
The two angles with x in their numerical value are added to get 108
Solution
10x + 2 + 4x + 8 = 108 Collect like terms
14x + 10 = 108 Subtract l0 from both sides.
14x + 10 -10 = 108 - 10 Collect like terms
14x = 98 Divide by 14
x = 98/14
x = 7
Answer:
79°
Step-by-step explanation:
since this figure goes around completely, the sum would be 360°
1 and 3 are equal, so you would multiply 101 by 2
101 × 2 = 202
subtract 202 from 360
360 - 202 = 158
4 and 2 are equal, so divide 158 by 2
158 ÷ 2 = 79
so angle 4 = 79°
All you would have to do is plug in 5 for t since that is the time; then you would see that the height of the object after 5 seconds is 886 ft. Hope this helped!
