Question

Find three consecutive integers who’s sum is 552

Answer 1

Here we will use algebra to find three consecutive integers whose sum is 552.

We assign X to the first integer. Since they are consecutive, it means that the 2nd number will be X+1 and the third number will be X+2 and they should all add up to 552. Therefore, you can write the equation as follows:

$X + X + 1 + X + 2 = 552$

To solve for X, you first add the integers together and the X variables together. Then you subtract 3 from each side, followed by dividing by 3 on each side. Here is the work to show our math:

$X + X + 1 + X + 2 = 552$

$3X + 3 = 552$

$3X + 3 - 3 = 552 - 3$

$3X = 549$

$\frac{3X}{3} = \frac{549}{3}$

$X = 183$

Which means that the first number is 183, the second number is 183+1 and third number is 183+2. Therefore, three consecutive integers that add up to 552 are:

183

184

185

Since, 183 + 184 + 185 = 552, it confirms that the answer above is correct.

Answer 2

Hey there!!

Let us take the first number as ' x '

The second number would be ' x + 1 '

The third number would be ' x + 2 '

If we add them, we get = 552

x + x + 1 + x + 2 = 552

3x + 3 = 552

Subtracting 3 on both sides

3x = 549

Dividing by 3 on both sides

x = 183

second number = 184

third number = 185

The numbers are = 183 , 184 , 185

Hope my answer helps!

Mark as brainliest if helps!