Answer:
The quadratic equation is x^2-2x-4
Step-by-step explanation:
We want to know the equation that has the solution below;
x = 1 ± √5
This means x = 1 + √5 or 1 - √5
The equation would thus be;
(x-1-√5)(x-1+ √5)
= x(x-1+ √5)-1(x-1+ √5)-√5(x-1+ √5)
Opening the brackets we have ;
x^2-x+ √5x-x + 1 -√5-√5x+ √5-5
collecting like terms we have;
x^2-2x+1-5
= x^2-2x-4
Answer:
x=-3
Step-by-step explanation:
2
−
1
⋅
1
2
=
6
2-1 \cdot \frac{12}{x}=6
2−1⋅x12=6
Solve
1
Combine multiplied terms into a single fraction
2
−
1
⋅
1
2
=
6
2
+
−
1
⋅
1
2
=
6
2
Multiply the numbers
2
+
−
1
⋅
1
2
=
6
2
+
−
1
2
=
6
3
Subtract
2
2
2
from both sides of the equation
2
+
−
1
2
=
6
2
+
−
1
2
−
2
=
6
−
2
4
Simplify
Subtract the numbers
Subtract the numbers
−
1
2
=
4
5
Multiply all terms by the same value to eliminate fraction denominators
−
1
2
=
4
⋅
−
1
2
=
⋅
4
6
Simplify
Cancel multiplied terms that are in the denominator
Re-order terms so constants are on the left
−
1
2
=
⋅
4
-12=x \cdot 4
−12=x⋅4
−
1
2
=
4
-12=4x
−12=4x
−
1
2
=
4
7
Divide both sides of the equation by the same term
−
1
2
=
4
−
1
2
4
=
4
4
8
Simplify
Divide the numbers
Cancel terms that are in both the numerator and denominator
Move the variable to the left
=
−
3
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Solution
=
−
3
4x^2(2x+1)-9(2x+1)=0
(4x^2-9)(2x+1)=0
(2x-3)(2x+3)(2x+1)=0
