All categories

2 years ago

Help PLEASEEEE

Mathematics

1 answer:

Bumek [7]2 years ago

3 0

Answer:

Segment AC = 10 units

segment AD =

angle 1 = 45°

angle 2 = 90°

AE = BE = CE = DE = 5

SEGMENT AC = AE + CE

= 5 + 5

= 10 UNITS

SEGMENT AD = 5² + 5²

= √50

= 7.071

= 7 UNITS

ANGLE 1 = 90° ÷ 2

= 45°

ANGLE 2 = 360° ÷ 4 / 180° ÷ 2

= 90°

You might be interested in

If the two lines 2x + y= 0 and y=3 are plotted on a typical xy coordinate grid, at which point will they intersect?

irina1246 [14]

2x + y = 0
2x + 3 = 0
      - 3 - 3
      2x = -3
   2     2
   x = -1¹/₂
(x, y) = (-1¹/₂, 3)

5 0

3 years ago

Read 2 more answers

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

Step 6: Find Slope at Given Point

[Algebra] Substitute in x: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

6 0

2 years ago

Read 2 more answers

Can one of you guys help me please :( thank you

timurjin [86]

Answer:

42???

Step-by-step explanation:

sorry if wrong

hope this helps

5 0

3 years ago

Read 2 more answers

Which of the relations had a domain of (-5,0,5)

tigry1 [53]

Answer:

Relation B had a domain of -5,0,5

Hope that helped

*befri.stends

Step-by-step explanation:

7 0

3 years ago

Angle Relationship

yaroslaw [1]

Answer:

B. 0.83

Step-by-step explanation:

I calculated it logically

7 0

2 years ago

Read 2 more answers