Answer:
it is - 15 please mark me brainliest
![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B64%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B0%5Cqquad%20%5Ctextit%7Bfrom%20the%20ground%7D%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.
A nonagon has 9 sides, so n = 9
S = sum of the interior angles
S = 180*(n-2)
S = 180*(9-2)
S = 180*7
S = 1260
Answer is choice B
Answer:
A. 3.5
Step-by-step explanation:
The perimeter is just the sum of all of the side lengths. The sides of this triangle are n inches, (n + 5.2) inches, and (2n + 3.4) inches.
So, your equation is n + n + 5.2 + 2n + 3.4 = 22.6 inches.
You can combine like terms (adding together all of the n's and all of the numbers) to simplify your equation to 4n + 8.6 = 22.6 inches.
Subtract 8.6 from both sides of the equation to get 4n = 14, and divide both sides by 4 to get n = 3.5.
Hope this helps! :)
Area of square= s^2
12.25=s^2
take the sqrt(12.25) = 3.5
Perimeter of square = 4s
P=4(3.5)
P= 14 m
