First angle to the right inside the triangle can be 60
Other angle inside the triangle can be 40
The upper angle outside the triangle 80
The last angle 100
Im not sure but I think it’s Y/2-2 (the y and 2 is a fraction)
Step-by-step explanation:
Your problem → 5y+5/2 / 25y-20/40y^2-32y
5y+5/2÷25y-20/40y^2-32y
=5⋅y+5/2÷25×y-20/40×y^2-32×y
=5y+5/2÷25×y-20/40×y^2-32y
=5y+5/2×1/25×y-20/40×y^2-32y
=5y+y/10-20/40×y^2-32y
=5y+y/10-y^2/2-32y
=5y×10+y-y^2×5-32y×10 ÷ 10
=50y+y-5y2-320y ÷ 10
= -269y-5y^2 / 10
The quotient of a number and four increased by three.
Have a good afternoon!!!!
Answer:
y = -3x + 21
Step-by-step explanation:
(5,6)
y = mx + b
6 = -3 × 5 + b
solving for b
b = 6 - (-3)(5)
b = 21
Therefore,
y = -3x + 21
