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Andreas93 [3]
2 years ago
12

Find the value of x. Round to the nearest tenth.

Mathematics
2 answers:
mel-nik [20]2 years ago
6 0

Answer:

the answer is 38.5

Step-by-step explanation:

Natalka [10]2 years ago
3 0

Answer: i need the fulll quetion

Step-by-step explanation:

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Help me with problems 13 ,14 and 15
Tamiku [17]
|2.5| because 2 and 1/2 are also 2.5 written in decimal, and the absolute value is always positive
8 0
3 years ago
Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0
3 years ago
Read 2 more answers
What is 28% as a fraction
marysya [2.9K]
Percent means parts out of 100
28%=28/100=14/50=7/25
3 0
3 years ago
Read 2 more answers
Sam’s basketball team won 70% of the games they played. How many games did they win?
maw [93]
Assuming it’s out of 100 it would 70 games they have won, but if it provides a number you will need to provide that for the correct answer.
7 0
3 years ago
Read 2 more answers
Solve each given equation and show your work. Tell whether each question has one solution, an infinite number of solutions, or n
laiz [17]
2x + 4(x - 1) = 2 + 4x
2x + 4x - 4 = 2 + 4x
6x - 4 = 2 + 4x
6x - 4x = 2 + 4
2x = 6
x = 3........there is 1 solution

25 - x = 15 - (3x + 10)
25 - x = 15 - 3x - 10
25 - x = -3x + 5
3x - x = 5 - 25
2x = - 20
x = -20/2
x = -10.....there is 1 solution

4x = 2x + 2x + 5(x - x)
4x = 4x + 5x - 5x
4x = 4x......this has infinite solutions

learn this...
if ur equation ends in a variable equaling a number, then there is one solution.
if ur equation ends in something not equal, like 2 = 4, or 4 = 6, then there is 0 solutions.
if ur equation ends in something equal to something,(the same) like 2 = 2, or 4x = 4x, then there is infinite solutions

3 0
3 years ago
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