All categories

2 years ago

What is 2000 dividable by

Mathematics

1 answer:

kirill115 [55]2 years ago

4 0

Answer:

Step-by-step explanation:

everything is!!!

You might be interested in

Answer question worth 25 points plz help!

Ilya [14]

Answer:

Step-by-step explanation:

6 0

3 years ago

Simplify the expression. Write your answer as a power. 6^10/6^4

vladimir2022 [97]

Answer:

6^6

Step-by-step explanation:

Divide the terms with the same base by subtracting their exponents.

6^10 - 4 = 6^6

8 0

3 years ago

Read 2 more answers

The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.

valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.85}{2} = 0.075$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.075 = 0.925$ , so Z = 1.44.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that $\sigma = \sqrt{1.69} = 1.3$

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.14 = 1.44\frac{1.3}{\sqrt{n}}$

$0.14\sqrt{n} = 1.44*1.3$

$\sqrt{n} = \frac{1.44*1.3}{0.14}$

$(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2$

$n = 178.8$

Rounding up

A sample of 179 is needed.

7 0

3 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

3 years ago

Simplify these expressions. a.2r+3+4r. b.8+3d+d. c.mn+ (-3mm)+6 d. 10s + (-10) + (-4s)

Maru [420]

Step-by-step explanation:

Combine like terms

a. 2r + 3 + 4r = (2r + 4r) + 3 = 6r + 3

b. 8 + 3d + d = (3d + d) + 8 = 4d + 8

c. mn + (-3mn) + 6 = (mn - 3mn) + 6 = -2mn + 6

d. 10s + (-10) + (-4s) = (10s - 4s) - 10 = 14s - 10

Terms are called "like terms" if they have the same variable part (the same letters in the same powers). Like terms differ at most coefficient.

7 0

3 years ago

What is 2000 dividable by​

What is 2000 dividable by