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3 years ago

Which postulate or theorem proves that △ABC and △CDA are congruent?

Mathematics

2 answers:

kvv77 [185]3 years ago

7 0

The answer would be the ASA Postulate because of the fact that the two opposite angles are congruent and the line crossing the rectangle is congruent to itself (reflexive Property)

DerKrebs [107]3 years ago

5 0

Answer:

ASA congruence postulate

Step-by-step explanation:

The ASA (Angle-Side-Angle) congruence postulate states that if two triangles have two angles and the included side (the side between the vertices of the two angles) congruent, then the triangles are congruent.

The two congruent angles are ∠ACB ≅ ∠CAD and ∠CAB ≅ ∠DCA. The included side is segment AC

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Jason and Maria are playing a board game in which three dice are tossed to determine a player's move. Find each probability for:

fredd [130]

Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,

P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.

P(three 5s) = (1 x 1 x 1)/216 = 1/216

P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36

6 0

3 years ago

CORRECT AND CLEAR ANSWER WILL BE GIVEN BRAINLIEST An object of mass 0.30 kg is thrown vertically upwards and reaches a height of

Natalka [10]

Answer:

Final potential energy = 24 Joule

The velocity with which object must be thrown = $4 \sqrt{10}$ m/s

Step-by-step explanation:

Given:

Mass of object, m = 0.30 Kg

Height of object, h = 8 m

Acceleration due to gravity, g = 10 $ms^{-2}$

a) Formula for Potential Energy:

$E_p =mgh$

Where m is the mass of object

g is acceleration due to gravity and

h is the height of object

Putting the values of m, g and h

$E_p = 0.3 \times 10 \times 8\\\Rightarrow E_p =24 J$

b) Formula for initial and final velocity:

$v^{2} =u^{2} +2gh$

where v is the final velocity

u is the initial velocity with which the object is thrown

g is acceleration due to gravity and

h is the height obtained by object

here v = 0 at the height 8 m because it will come to rest at the point it attains the maximum height.

h = 8m

g = -10 $ms^{-2}$ (negative because the object's velocity is decreasing)

Putting the values to find 'u':

$0^{2} =u^{2} +2 \times -10 \times 8\\\Rightarrow u^{2} = 160\\\Rightarrow u = 4 \sqrt{10}\ m/s$

7 0

3 years ago

X-2(x+3) help me plzz.

AveGali [126]

Answer:

divide with the 3 first

Step-by-step explanation: Then the rest

4 0

3 years ago

Only you have to answer the question 1 from the diagram

Fantom [35]

ADC = 40 + 30 = 70 degrees

DBC is given at 45 deg

AEB = 100 degrees, vertical angle from intersecting lines

BCD = 50 + 50 = 100 degrees

5 0

3 years ago

the volume of a rectangular cardboard box is modeled by the functions v(x)=(18-2x)(3-2x)x where x is the width

ohaa [14]

Answer:

The given function of volume v(x)=(18-2x)(3-2x)x is true for certain boundaries of x which is mentioned below.

Step-by-step explanation:

The equation for the volume is represented as:

v(x)=(18-2x)(3-2x)x

As x represents the width, it cannot be negative or zero. X must be greater than 0.
For the equation (18-2x), the term can't be negative or zero so,

18-2x > 0

or, 2x < 18

or, x < 9

For the term, 3-2x > 0

or, 2x < 3

or, x < 1.5

This develops the boundary for x as,

0 < x < 1.5

6 0

3 years ago