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GenaCL600 [577]
3 years ago
8

Help please Simplify the expression: (a^5)^3 * A.a^8 B.a^2 C.a^15 D.a^(-2)

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

D

Step-by-step explanation: im smart

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The Answer is b. Hope that helps
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3 years ago
Classify the numbers by writing them in the appropriate section of the Venn Diagram 1) L. 136, 8, 7, V140, V4,8, V8 , 2.89 Real
saveliy_v [14]

<em>EXPLANATION:</em>

Classification of numbers according to the Venn diagram:

<em>Rational numbers:</em>

These numbers are represented by a fraction a / b, where a and b are integers and also b is different from zero.

<em>Whole numbers</em><em>:</em>

An integer is a natural number that can be positive or negative.

<em>Natural numbers:</em>

Natural numbers are those that start at zero to infinity are clearly positive.

<em>Rational numbers:</em>

When taking the square root of 8, 36 and 4 the result is an exact value that is why they are considered as rational numbers.

<em>Irrational Numbers:</em>

When the root of a number is not exact but is expressed as an infinite decimal as in the case of the square root of 140 which is 11.83215956619; this is an irrational number, also this result cannot be expressed as a fraction.

4 0
1 year ago
Which statement is true
deff fn [24]
I would say the answer is D.
6 0
3 years ago
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14. DECORATING Sabrina is decorating her
Nikitich [7]

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3 0
3 years ago
A research engineer for a tire manufacturer is investigating tire life for a new rubber compound. She has built 10 tires and tes
n200080 [17]

Answer:

The standard deviation of tire life does exceed 3000 km

Step-by-step explanation:

This is a Chi-Square Hypothesis Test for the Standard Deviation, here we have

\bf H_0: \sigma = 3000

\bf H_a: \sigma > 3000

so, this is an upper one-tailed test.

The <em>test statistic</em> is

\bf T=\frac{(n-1)s^2}{\sigma^2}

where

<em>n = 10 is the sample size</em>

<em>s = sample standard deviation</em>

\bf \sigma = population standard deviation

we would reject the null hypothesis if

\bf T>\chi^2_{(\alpha,n-1)}

where

\bf \chi^2_{(\alpha,n-1)}

is the critical value corresponding to the level of significance \bf \alpha with n-1 degrees of freedom.

we can use either a table or a spreadsheet to compute this value.

In Excel use

CHISQ.INV(0.05,9)

In OpenOffice Calc use

CHISQINV(0.05;9)

and we get this value equals 3.3251

Working out our T statistic

\bf T=\frac{(n-1)s^2}{\sigma^2}=\frac{9*(2990)^2}{(3000)^2}=8.9401

Since T > 3.3251 we reject the null and conclude that the standard deviation of tire life exceeds 3000 km.

7 0
3 years ago
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