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2 years ago

Different network scenarios require the

Computers and Technology

1 answer:

Vladimir [108]2 years ago

4 0

Answer:

a) Viruses

Explanation:

Vulnerability assessment is performed by variety of tools and these can be protocol analyzer, vulnerability scanner, Honeypots, port scanners, honey nets and banner grabbing tools.

Port scanners : they are used to scan the ports which can be exploited by attackers. Most of TCP/IP applications communicate using different ports and attackers can exploit these ports if they are found vulnerable. for example : ports like 80 and 443 are commonly used for HTTP and SSL communication. 22 is used for SSH and if they are open to world then it will allow attackers to use those to get the entry into the system.

Protocol Analyzers : They are used to analyze the packet captures. tools like wireshark, tshark, these tools will help user to decode HTTP/SSL/HTTPS/FTP/RSTP or any application protocols communication. this will help user to understand any unwanted or non-anticipated traffic.

Vulnerability Scanners : They are used to detect the vulnerabilities in the network or systems. these will help administrators to get the alerts whenever there are unanticipated activity. It will have two types of scanners one is active scanner and other is passive scanner. Active scanners will keep on sending probes at the fixed time slots and passibe scanners will be in listening mode all the time. These scanners will alert when a new nodes comes up or goes down or if any system gets compromised.

Honeypots and Honey nets : They are devices or softwares which are having limited security. These devices are made vulnerable purposefully so that attackers can try and attack. This will help softwares to detect the attackers when they try to exploit these open vulnerabilities. They are deceptions created with purpose.

Banner grabbing Tools : These are tools which will capture the banner information like HTTP protocol version, underlying operating system, open ssl versions being used, server software and similar information. these are important as it will open up potential vulnerabilities in the underlying software. for ex : SSLv3 has a vulnerability known to world and can be exploited by anyone.

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Your baby brother has found the hammer and is eagerly eyeing one of the boxes. Describe and analyze an algorithm to determine if

erastovalidia [21]

Answer:

Question is incomplete.

Assuming the below info to complete the question

You have a collection of n lockboxes and m gold keys. Each key unlocks at most one box. Without a matching key, the only way to open a box is to smash it with a hammer. Your baby brother has locked all your keys inside the boxes! Luckily, you know which keys (if any) are inside each box.

Detailed answer is written in explanation field.

Explanation:

We have to find the reachability using the directed graph G = (V, E)

In this V are boxes are considered to be non empty and it may contain key.

Edges E will have keys .

G will have directed edge b1b2 if in-case box b1 will have key to box b2 and box b1 contains one key in it.

Suppose if a key opens empty box or doesn’t contain useful key means can’t open anything , then it doesn’t belongs to any edge.

Now, If baby brother has chosen box B, then we have to estimate for other boxes reachability from B in Graph G.

If and only if all other boxes have directed path from box B then just by smashing box B we can get the key to box b1 till last box and we can unlock those.

After first search from B we can start marking all other vertex of graph G.

So algorithm will be O ( V +E ) = O (n+m) time.

7 0

3 years ago

Could anyone please answer this?

Anastaziya [24]

Answer:

Explanation:

The answer is D because if you're looking for lightweight materials, you'll be dealing with chemistry, and chemistry is sience.

4 0

2 years ago

Which of the following is something that all computer models use in their calculations?

Rzqust [24]

The answer is 4 because all computers use variables to process something

8 0

3 years ago

computer has a 32-bit instruction word broken into fields as follows: opcode, six bits; two register file address fields, five b

lina2011 [118]

Answer:

a. 2^6, or 64 opcodes.

b. 2^5, or 32 registers.

c. 2^16, or 0 to 65536.

d. -32768 to 32768.

Explanation:

a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.

b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.

c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.

d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.

6 0

3 years ago

In this exercise, your function will receive 2 parameters, the name of a text file, and a list of strings. The function will wri

diamong [38]

Answer:

# the function is defined

# it takes 2 arguments: filename and list of string

def solution(filename, listOfString):

# the file is opened in write mode

# so that we can write to it

with open(filename, 'w') as file_object:

# we loop through the entire list of string

# this looping help us know what to write to the file

for each_string in listOfString:

# if the length of the string is less than 4

# we write 'x' with a new line

if len(each_string) < 4:

file_object.write("x\n")

# else if the length of the string is greater than equals 4

# we write the fourth character

# and also add new line

else:

file_object.write(each_string[3])

file_object.write("\n")

Explanation:

The function is written in Python. It takes two argument; filename and list of string.

It opens the file in write mode and then loop through the list of string. During the loop, we know what to write to the file.

In the length of a string is less than 4; we write 'x' else we write the fourth character in the string. The fourth character has an index of 3 because string uses zero index counting like a string. Starting from zero; 0, 1, 2, 3, 4... the fourth character has an index of 3.

5 0

3 years ago