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Mars2501 [29]
3 years ago
15

The height of a projectile in the air t seconds after it is shot can be modeled by the function y = -16t^2 + 3200t + 2, where t

and y are measured in feet. What is the maximum height that the projectile reaches?
Mathematics
1 answer:
Talja [164]3 years ago
5 0

Answer:

160002 feet

Step-by-step explanation:

y(t)=-16t^2+3200t+2

We need y’ to find a maximum

y’(t)=-32t+3200

y’(t)=0 if t=100

Notes that y’(t)>0 if t<100, and fot t>100 y’(t)<0. Now we can conclude that y(t) has maximum in t=100

Y(100)=-16*10000+3200*100+2

Y(100)=160002 feet

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3)Take the total distance, divide it by the total time to get the average speed.

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2 years ago
Factor completely x^4-17x^2+16​
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Answer:

(x - 1) (x + 1) (x - 4) (x + 4)

Step-by-step explanation:

actor the following:

x^4 - 17 x^2 + 16

x^4 - 17 x^2 + 16 = (x^2)^2 - 17 x^2 + 16:

(x^2)^2 - 17 x^2 + 16

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Factor the difference of two squares. x^2 - 4^2 = (x - 4) (x + 4):

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4 0
3 years ago
7x-2=5x+14<br> X=?<br> (step by step needed)
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Answer:

x = 8

Step-by-step explanation:

Step 1: Subtract 5x from both sides.

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Step 2: Add 2 to both sides.

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Step 3: Divide both sides by 2.

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Step 4: Check if solution is correct.

  • 7(8)-2=5(8)+14
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Therefore, x = 8.

8 0
2 years ago
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