Question

The height of a projectile in the air t seconds after it is shot can be modeled by the function y = -16t^2 + 3200t + 2, where t and y are measured in feet. What is the maximum height that the projectile reaches?

Answer 1

Answer:

160002 feet

Step-by-step explanation:

y(t)=-16t^2+3200t+2

We need y’ to find a maximum

y’(t)=-32t+3200

y’(t)=0 if t=100

Notes that y’(t)>0 if t<100, and fot t>100 y’(t)<0. Now we can conclude that y(t) has maximum in t=100

Y(100)=-16*10000+3200*100+2

Y(100)=160002 feet