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Stells [14]
3 years ago
9

Polynomial expressions with matching​

Mathematics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

The difference of 27x³ and 8y³ → [3x - 2y][9x² + 6xy + 4y²]

The difference of 27x³ and 64y³ → [3x - 4y][9x² + 12xy + 16y²]

The sum of 27x³ and 64y³ → [3x + 4y][9x² - 12xy + 16y²]

The sum of 27x³ and 8y³ → [3x + 2y][9x² - 6xy + 4y²]

Step-by-step explanation:

For the first two, we use the Difference of Cubes [(a³ - b³)(a² + 2ab + b²)] first by taking the cube root of the given expression to get our first factor[s]:

\displaystyle 3x - 2y = \sqrt[3]{27x^3 - 8y^3} \\ 3x - 4y = \sqrt[3]{27x^3 - 64y^3}

Then, use the acronym of SOAP {whether the next operations symbols will be negative or positive [SAME (your cube-rooted factor has an IDENTICAL OPERATION SYMBOL as your given expression), OPPOSITE (the first sign in your second factor in the second set of parentheses will be the opposite of what the sign in your given expression, which will be a plus sign), ALWAYS POSITIVE (the last sign in your second factor in the second set of parentheses will ALWAYS stay positive NO MATTER WHAT)]} to get the second factor:

Given: 27x³ - 64y³

[3x - 4y][9x² + 12xy + 16y²]

↑ ↑ ↑

same as opposite ALWAYS POSITIVE

given of given

Given: 27x³ - 8y³

[3x - 2y][9x² + 6xy + 4y²]

↑ ↑ ↘

same as opposite ALWAYS POSITIVE

given of given

Now, for the last two, we use the Sum of Cubes [(a³ + b³)(a² - 2ab + b²)] first by taking the cube root of the given expression to get our first factor[s]:

\displaystyle 3x + 2y = \sqrt[3]{27x^3 + 8y^3} \\ 3x + 4y = \sqrt[3]{27x^3 + 64y^3}

Then, use the acronym of SOAP {whether the next operations symbols will be negative or positive [SAME (your cube-rooted factor has an IDENTICAL OPERATION SYMBOL as your given expression), OPPOSITE (the first sign in your second factor in the second set of parentheses will be the opposite of what the sign is in your given expression, which will be a minus sign), ALWAYS POSITIVE (the last sign in your second factor in the second set of parentheses will ALWAYS stay positive NO MATTER WHAT)]} to get the second factor:

Given: 27x³ + 64y³

[3x + 4y][9x² - 12xy + 16y²]

↑ ↑ ↘

same as opposite ALWAYS POSITIVE

given of given

Given: 27x³ + 8y³

[3x + 2y][9x² - 6xy + 4y²]

↑ ↑ ↘

same as opposite ALWAYS POSITIVE

given of given

I am delighted to assist you anytime!

* As you can see, when using the <em>Difference\Sum of Cubes</em>, SOAP can vary depending on how an expression is given to you. They resemble each other though.

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Step-by-step explanation:

The function definition tells you that adding 12 to the x-value will give you the value of f(x).

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The (x, f(x)) values for the table are shown above.

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Farmer Ed has 9,500 meters of fencing,
Andreas93 [3]

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get:</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: </em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for x</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equation</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distribute</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y </em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y You can see that this is a parabola which opens down, meaning that the point of maximum area will be at the vertex, y = </em><em>- </em><em>b</em><em>/2a = -7500/[2(-2)] = 1875</em>

<em>/2a = -7500/[2(-2)] = 1875 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2 </em>

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Given that rectangle LMNO with coordinates L(0,0), M(3,0), N(3,7), O(0,7), P is the midpoint of LM⎯⎯⎯, and Q is the midpoint of
Elina [12.6K]

The midpoint of a line divides the line into equal segments.

The option that proves PQ = LO is (a)

The given parameters are:

\mathbf{L = (0,0)}

\mathbf{M = (3,0)}

\mathbf{N = (3,7)}

\mathbf{O = (0,7)}

P is the midpoint of LM.

So, we have:

\mathbf{P = \frac{LM}{2}}

\mathbf{P = (\frac{(0 +3}{2},\frac{0+0}{2})}

\mathbf{P = (\frac{3}{2},0)}

Q is the midpoint of NO.

So, we have:

\mathbf{Q = \frac{NO}{2}}

\mathbf{Q = (\frac{(3 +0}{2},\frac{7+7}{2})}

\mathbf{Q = (\frac{3}{2},7)}

Distance PQ is calculated as follows:

\mathbf{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

This gives:

\mathbf{PQ = \sqrt{(3/2 - 3/2)^2 + (0 - 7)^2}}

\mathbf{PQ = \sqrt{ 7^2}}

\mathbf{PQ = 7}

Distance LO is calculated as follows:

\mathbf{LO = \sqrt{(0 - 0)^2 + (0 - 7)^2}}

\mathbf{LO = \sqrt{ 7^2}}

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So, we have:

\mathbf{PQ = 7}

\mathbf{LO=7}

Thus:

\mathbf{PQ = LO}

Hence, the correct option is (a)

Read more about distance and midpoints at:

brainly.com/question/11231122

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