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blagie [28]
2 years ago
14

What is the length of GH¯¯¯¯¯¯, to the nearest tenth of a meter? 7.3 m 13.7 m 14.1 m 19.4 m A scalene triangle G H J. The base s

ide is J H. Side G J is labeled as 10 meters. Angle J is labeled as 45 degrees. Angle H is labeled as 31 degrees.

Mathematics
2 answers:
nlexa [21]2 years ago
8 0
By applying the law of sines.

\frac{GH}{sin \ J} =  \frac{GJ}{sin \ H}

Given:
<span>GJ = 10 , ∠J =45° , ∠H = 31°

∴ </span><span>\frac{GH}{sin \ 45} =  \frac{10}{sin \ 31}

∴ GH = 10 * sin 45° / sin 31° ≈ 13.7 m
</span>
attashe74 [19]2 years ago
7 0

Answer:

13.7 m

Proof in Pic:

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Mark all the integers below.
seropon [69]
Answer is 9.12 thanks for using brainly
4 0
3 years ago
Help fast please k it dued today
Dmitry_Shevchenko [17]

Answer:

1. -72

2. -66

Step-by-step explanation:

Hope this helps you       :)

8 0
3 years ago
Mona wrote 7 tests, and her test average is 93. There will be one more test before the end of the year. What is the lowest grade
olga55 [171]
For this case, the first thing we are going to do is assume that all the tests are worth the same.
 Then, we define a variable:
 x: score of Mona's last test
 We write now the inequality that models the problem:
 \frac{93 + x}{2}  \geq  90
 From here, we clear the value of x: 93 + x  \geq  90*(2) &#10;&#10;93 + x  \geq  180&#10;&#10; x  \geq  180 - 93&#10;&#10; x  \geq  87
 Answer:
 
the lowest grade that Mona can get for her last test so that her test average is 90 or more is:
 
x = 87
8 0
3 years ago
Simplify 9(30 - 2).<br> 252<br> 288<br> 272<br> 268
Lapatulllka [165]
28
x 9
___
72
+180
____
252

The answer is 252
___
8 0
2 years ago
Write the equation of the parabola in vertex form with vertex at (2,-5) and y intercept at -17.
jok3333 [9.3K]
<h3>Answer:</h3>

y = -3(x -2)² -5

<h3>Explanation:</h3>

The equation of a parabola with vertex (h, k) is given by ...

... y = a(x -h)² +k . . . . . . . for some vertical scale factor "a".

We can find the value of "a" by substituting the coordinates of a point that is not the vertex. Here, that point is the y-intercept: (0, -17).

... y = a(x -2)² -5 . . . . . initial form of the equation for the parabola

... -17 = a(-2)² -5 . . . . . substitute y-intercept values

... -12 = 4a . . . . . . . . . . add 5, simplify

... -12/4 = a = -3

The desired equation is ... y = -3(x -2)² -5.

4 0
3 years ago
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