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alexira [117]
2 years ago
9

Solve each equation

D%7Bx-3%7D%3D0" id="TexFormula1" title="\frac{3x-2}{x+ 4} =0\\\\\\\frac{2}{x-3}=0" alt="\frac{3x-2}{x+ 4} =0\\\\\\\frac{2}{x-3}=0" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Sloan [31]2 years ago
4 0

The expression (3x - 2)/(x + 4) = 0 has a value of x is 3/2. Amd the expression 2/(x + 4) = 0 has a value of x is ∞.

<h3>What is simplification?</h3>

Simplification is to make something easier to do or understand and to make something less complicated.

The expression is given below.

(3x - 2)/(x + 4) = 0

Then on simplifying, we have

3x - 2 = 0

    3x = 2

      x = 3/2

And

2/(x - 3) = 0

         2 ≠ 0

More about the simplification link is given below.

brainly.com/question/12616840

#SPJ1

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Please help me with this question. I am very confused.
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8 0
2 years ago
What is the discontinuity and zero of the function f(x) = 3x^2 + x - 4 / x-1
7nadin3 [17]
Ans: Option (1) <span>Discontinuity at (1, 7), zero at ( negative four thirds , 0) 
</span>
Explanation:
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f(x) =  \frac{3x^2 + x - 4}{x-1}

Now if we plug in the x = 1, we would have discontinuity as function goes to infinity.

Now for f(1):
f(x) = \frac{3x^2 + x - 4}{x-1} \\ f(x) = \frac{3x^2 + 4x - 3x - 4}{x-1} \\ f(x) = \frac{x(3x+4)-1(3x+4)}{x-1} \\ f(x) = \frac{(x-1)(3x+4)}{(x-1)} \\ f(x) = 3x+4 \\ now ~ insert ~ x=1: \\ f(1) = 3(1) + 4 = 7 \\ It~means~discontinuity~at~(1,7).\\ Now~let~us~find~zeros.\\ put~ f(x) = 3x+4 ~ equals~ to ~zero. \\ =\ \textgreater \ ~3x+4 = 0 \\ =\ \textgreater \  ~ x =  \frac{-4}{3} \\ Hence~zeros=(  \frac{-4}{3}, 0)

5 0
3 years ago
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