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EleoNora [17]
3 years ago
10

The area of a rectangle is (x4 + 4x3 + 3x2 – 4x – 4), and the length of the rectangle is (x3 + 5x2 + 8x + 4). If area = length ×

width, what is the width of the rectangle?
Mathematics
2 answers:
astraxan [27]3 years ago
8 0

Answer:

Width = x-1

Step-by-step explanation:

Given

Area of rectangle=A= x^4+4x^3+3x^2-4x-4

Length of Rectangle=L= x^3+5x^2+8x+4

We have to find width

Width of rectangle=W= ?

We know that the formula for the area of triangle is:

Area of Rectangle=Length*Width

A=L*W

Since we need the value of width, length will be moved to the left of equals to.

A/L=W

W= (x^4+4x^3+3x^2-4x-4)/(x^3+5x^2+8x+4)

After long division, we will get

Width=W=x-1

goldfiish [28.3K]3 years ago
3 0

Answer: D. "x-1"

Step-by-step explanation:

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This has to be done by hit and trial method. i.e. you have to checking adding which of the function from first column to function in second column will yield h(x).

The following functions yield given value of h(x).

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8 0
3 years ago
Consider triangle GHJ.
bulgar [2K]

we know that

<u>Applying the Pythagorean Theorem</u>

JG^{2} =HJ^{2}+HG^{2}

solve for HJ

HJ^{2}=JG^{2}-HG^{2}

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JG=10\ units\\ HG= 5\ units

Substitute the values in the formula above

HJ^{2}=10^{2}-5^{2}

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therefore

<u>the answer is the option</u>

B. 5 sq. root 3 units

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3 years ago
Read 2 more answers
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