Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer:
angle bisector theorem
Step-by-step explanation:
the angle bisector theorem tells us that if an angle is cut by a bisector than it willl be equally cut and congruent
Answer:
x>22
Step-by-step explanation:
Solve the inequality:
-3x<-14-52
-3x<-66
x>22
( You have to switch the sign because you are dividing by a minus)
Answer:
first top left graph? 12×4 is 48 so that puts it about right
