Answer: do ya own work luv
Step-by-step explanation:
Answer:
The answer is 3.5 mph
Step-by-step explanation:
30 x 2 = 60 minutes = 1 hour
1.75 x 2 = 3.5 miles
So 3.5 miles in 1 hour
3.5 mph
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
The length of the diagonal support is 69 feet.
Step-by-step explanation:
Dimensions of the box: length = 6 feet
width = 5 feet
height = 8 feet
The diagonal support relates with the diagonal of the base and the height.
From the base of the box, let the length of its diagonal be represented by x. Applying Pythagoras theorem;
= 
+ 
= 
+ 
= 36 + 25
= 61
x = 
= 7.81
let the length of the diagonal support be represented by l. So that;
= +
= + 
= + 64
l = 
= 61 + 8
= 69
Thus, the length of the diagonal support is 69 feet.
You can use a square plus b square equal C square to fijd each length . or you can memorize the special triangles or you can also do proportional problem. it all works
