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Mkey [24]
3 years ago
11

Does the expression 2b + 5b have like terms?

Mathematics
2 answers:
Soloha48 [4]3 years ago
3 0

Answer:

Yes. 'b' is a like term

Step-by-step explanation:

ValentinkaMS [17]3 years ago
3 0

The two terms have the same variable, B. This allows us to add them together directly. 2B + 5B = 7B

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Estimate 4/5 times 1 8/9
goldfiish [28.3K]

Answer:

1 23/45 ???

Step-by-step explanation:

I am not sure if im right.

3 0
3 years ago
Someone please help me in this question it is kind of confusing it is a question under pre calculus in first year calculus i wil
masya89 [10]
Neither P, nor A are on the sketch 
I guess P is the upper right corner of the rectangle 
and A=(0,1) 

P belongs to the line going through (1,0) and B(0,y) 
<span>but we don't know the y-coordinate of B </span>

<span>the triangle is right and isosceles, so pythagoras a²+a²=2² ... 2a²=4 ... a²=2 ... a=sqrt2 </span>
now look at the right triangle BOA 
<span>his hypotenuse is AB=sqrt2 and the <span>the kathete</span> OA is 1 </span>
so y²+1²=(sqrt2)² ... y²+1=2 ... y²=1.. y=1 
so the coordinates of B are (0,1) 

the line going through (1,0) and (0,1) is L(x)=-x+1 

P belongs to this line, so the coordinates of P are P(x,-x+1) (0<x<1) 

b) so if that's P, the height of the rectangle is -x+1 and the width=2x 
<span>so its area A(x)=2x*(-x+1)= -2x²+2x 

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

</span>
5 0
3 years ago
a triangle has a perimeter of 10x+2 . two sides have lengths of 5x and 2x+9 what is the length of the 3rd side
stiks02 [169]
Since all the sides add up to 10x+2, that means that 10x-2-<side1>-<side2>=<side3>. Plugging it in, we have 10x-2-5x-(2x+9)=side3, and 5x-2-(2x+9)=side3, then expanding it to 5x-2-2x-9=3x-11=side3
8 0
3 years ago
(Photo attached) Trig question. Thanks in advance! :)
kolbaska11 [484]

Answer:

  a) cos(α+β) ≈ 0.8784

  b) sin(β -α) ≈ -0.2724

Step-by-step explanation:

There are a couple of ways to go at these. One is to use the sum and difference formulas for the cosine and sine functions. To do that, you need to find the sine for the angle whose cosine is given, and vice versa.

Another approach is to use the inverse trig functions to find the angles α and β, then combine those angles and find find the desired function of the combination.

For the first problem, we'll do it the first way:

  sin(α) = √(1 -cos²(α)) = √(1 -.926²) = √0.142524 ≈ 0.377524

  cos(β) = √(1 -sin²(β)) = √(1 -.111²) ≈ 0.993820

__

a) cos(α+β) = cos(α)cos(β) -sin(α)sin(β)

  = 0.926×0.993820 -0.377524×0.111

  cos(α+β) ≈ 0.8784

__

b) sin(β -α) = sin(arcsin(0.111) -arccos(0.926)) ≈ sin(6.3730° -22.1804°)

  = sin(-15.8074°)

  sin(β -α) ≈ -0.2724

4 0
4 years ago
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