I hoped this helped or something
Part 1:
For this case we must see in the graph the axis of symmetry of the given parabola.
We have then that the axis of symmetry is the vertical line t = 2.
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, observing the graph we see that:
h (3) = 20 feet
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
1. obtuse angle is shown, 45° is missing.
2. obtuse angle is shown, 29° is missing.
3. acute angle is shown, 65° is missing.
4. acute angle is shown, 40° is missing.
5. acute angle is shown, 42° is missing.
6. acute angle is shown, 100° is missing.
7 an obtuse angle and a acute angle are shown, 54° (for number 1) and 126° (for number 2) are missing.
8. an obtuse and a acute angle are shown, 45° (for 1) and 135° (for 2) are missing.
Answer:
The third one
Step-by-step explanation:
You would first mark -2 on a graph then the circle would be open because the sign is just greater than, then the arrow would be pointing to the right, because that is the way your equation shows it
The answer will also decrease.