Answer:
Step-by-step explanation:
x decreases w/o bound, so x becomes a very large -ve no.
f(x)=5^(x-1) becomes 5^(large -ve no.) which will be almost zero
x increases w/o bound, so x becomes a very large +ve no.
f(x)=5^(x-1) becomes 5^(large +ve no.) which will keep increasing w/o bound
if u provide wat the choices are from ur Q in comments, i will pick the right one 4 u
5x+3=3x+7
<em></em>-3 = -3
2x+3=7
-3= -3
2x=4
x=2
Step-by-step explanation:
1 2 3 4 5
wa
I think you can solve it by
=(x^2 - y^2) *( x^2 + y^2)
= (x -y)*(x+y)*(x^2 + y^2)
