Solve the equation z=2x+3 for x

AB is the angle bisector of CAD. Solve for the missing variable?

Alika [10]

Answer:

$x=8^\circ$

Step-by-step explanation:

A bisector is the line that divides an angle (which in this case is $\angle CAD$ ) exactly in half. Therefore, $\angle CAB = \angle BAD$ and as such we can solve for $x$ :

$\angle CAB &= \angle BAD\\33^\circ &= 4x + 1^\circ\\4x = 32^\circ\\x = 8^\circ$

and we are done.

4 0

3 years ago

Jenna found three solution to a linear equation she graphed them, but they don't lie in a straight line. What errors could jenna

steposvetlana [31]

Answer:

A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.

There are many different methods in arriving to the final answer. However, errors cannot be perfectly avoided. One of these errors to mistakenly identify equations as linear. It is important that we know that the equations we are dealing with are of exact or correct characteristics.

Also, if she had used substitution method, she might have mistakenly taken the value of one variable for the other.

5 0

3 years ago

9x + 2+ 5x = 23 +7<br><br> SOLVE pLEASE

yarga [219]

Answer:

2

Step-by-step explanation:

14x + 2 = 30

14x = 28

x = 2

8 0

3 years ago

Read 2 more answers

What is the height of the triangle? 12 units 24 units 36 units 72 units.

konstantin123 [22]

Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side. The height of the tringle is 24 units. Hence option 2 is the correct option.

<h3>Given information-</h3>

The triangle for the given problem is shown in the image below.

Form the figure the length of the each side is $16 \sqrt{3}$ units.

As all the sides are equal thus the $\Delta MNO$ is a equilateral triangle in which the height of the divides the triangle into two equal part of the length $8\sqrt{3}$ at point <em>R.</em>

<h3>Height of the triangle-</h3>

Height of the triangle is the altitude of the triangle and which is drawn perpendicular from the vertex of the triangle to the opposite side.

Now in the $\Delta MRN$ , the length of the hypotenuse is $16 \sqrt{3}$ units and the length of the base is $8\sqrt{3}$ units. Let <em>h </em>is the height of the triangle thus by the Pythagoras theorem,