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Snowcat [4.5K]
3 years ago
15

I don't understand the question.

Mathematics
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer:

Distribution means to spread the product throughout the marketplace such that alarmed number of people can buy it.

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Help me plzzzzzzzzz<br> solve for x
Svet_ta [14]

Answer:

7) \frac{x+20}{x}=\frac{46}{30}

30(x+20)=46x

30x+600=46x

46x-30x=600

16x=600

x=75/2

x=37.5

---------------------

8) \frac{10}{3x+1} =\frac{22}{7x-1}

10(7x-1)=22(3x+1)

70x-10=66x+22

70x-66x=22+10

4x=32

x=\frac{32}{4}

x=8

<u>---------------------</u>

hope it helps...

have a great day!!

4 0
3 years ago
Help me with this problem I will give brainliest
Inga [223]

Answer:

x=3

Step-by-step explanation:

7 0
3 years ago
4.
Ivenika [448]

Answer: The non solutions of the inequality are A and D.

Step-by-step explanation:

3 0
3 years ago
An experiment to investigate the survival time in hours of an electronic component consists of placing the parts in a test cell
mixer [17]

Answer:

a) The sample mean is of 49 and the sample standard deviation is of 11.7.

b) The range of the true mean at 90% confidence level is of 9.62 hours.

c) The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

Step-by-step explanation:

Question a:

Sample mean:

\overline{x} = \frac{34+40+46+49+61+64}{6} = 49

Sample standard deviation:

s = sqrt{\frac{(34-49)^2+(40-49)^2+(46-49)^2+(49-49)^2+(61-49)^2+(64-49)^2}{5}} = 11.7

The sample mean is of 49 and the sample standard deviation is of 11.7.

b)Determine the range of the true mean at 90% confidence level.

We have to find the margin of error of the confidence interval. Since we have the standard deviation for the sample, the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.0.150

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. So

M = 2.0150\frac{11.7}{\sqrt{6}} = 9.62

The range of the true mean at 90% confidence level is of 9.62 hours.

(c)If a seventh sample is tested, what is the prediction interval (90% confidence level) of its failure time.

This is the confidence interval, so:

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 9.62 = 39.38 hours.

The upper end of the interval is the sample mean added to M. So it is 49 + 9.62 = 58.62 hours.

The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

4 0
3 years ago
You have 5 pieces of wood. What is the total length of the wood? 73cm, 1.6m, 2.87m, 325cm and 4.04m
skad [1K]
First, you need to make sure that they're in the same measurement ration

1 m = 100 cm

so, now you have

73 cm + 160 cm + 287 cm + 325 cm + 404 cm

The total length would of all the wood would be be 1249 centimeters  or 12.49 meter 
8 0
3 years ago
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