I don't understand the question.
1 answer:
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Answer:
The ball is dropped from a height of 36 feet
The bee and the ball will collide after approximately 1.3 seconds
The bee and the ball will collide at approximately 8 feet above the ground
The ball hits the ground after 1.5 seconds
Step-by-step explanation:
<u><em>The complete question is</em></u>
A ball dropped from the top of the building can be modeled by the function f(t)=-16t^2 + 36 , where t represents time in seconds after the ball was dropped. A bee's flight can be modeled by the function, g(t)=3t+4, where t represents time in seconds after the bee starts the flight.
The graph represents the situation.
select all that apply
1) The bee launches into flight from the ground.
2) The ball is dropped from a height of 36 feet.
3) The bee and the ball will collide after approximately 1.3 seconds.
4) The bee and the ball will collide after approximately 8 seconds.
5) The bee and the ball will collide at approximately 8 feet above the ground.
6) The bee and the ball will not collide.
7) The ball hits the ground after 1.5 seconds
see the attached figure to better understand the problem
<u><em>Verify all the options</em></u>
case 1) The bee launches into flight from the ground.
The statement is false
Because
we have
For t=0
That means ----> The bee launches into flight from a height 4 feet above the ground
case 2) The ball is dropped from a height of 36 feet
The statement is true
Because
For t=0
case 3) The bee and the ball will collide after approximately 1.3 seconds
The statement is true
Because
Equate f(t) and g(t)
solve the quadratic equation by graphing
The solution is t=1.324 sec
see the attached figure N 2
case 4) The bee and the ball will collide after approximately 8 seconds
The statement is false
Because, the bee and the ball will collide after approximately 1.3 seconds (see case 3)
case 5) The bee and the ball will collide at approximately 8 feet above the ground
The statement is true
Because
For t=1.324 sec
substitute the value of t in f(t) or g(t)
case 6) The bee and the ball will not collide
The statement is false
see case 3) and case 5)
case 7) The ball hits the ground after 1.5 seconds
The statement is true
Because
we know that
The ball hit the ground when the value of f(t) is equal to zero
so
For f(t)=0
According to the temperature changes, it is found that:
- On Tuesday, the temperature at Noon was of -28.5 ºF.
- On Wednesday, the temperature at Midnight was of -5.5 ºF.
- On Thursday, the change was of -11.8 ºF.
- On Friday, the temperature at Noon was of -4.5 ºF.
- The temperature change during a period is given by the <u>temperature at the end of the period subtracted by the temperature at the start of the period</u>.
On Tuesday:
- At the start of the period, the temperature was of -17.5 ºF.
- The change was of -11 ºF.
Hence:
On Tuesday, the temperature at Noon was of -28.5 ºF.
On Wednesday:
- At the end of the period, the temperature was of 10 ºF.
- The change was of 15.5 ºF.
Hence:
On Wednesday, the temperature at Midnight was of -5.5 ºF.
On Thursday:
- At the end of the period, the temperature was of -24 ºF.
- At the start of the period, the temperature was of -12.2 ºF.
Hence:
On Thursday, the change was of -11.8 ºF.
On Friday:
- At the start of the period, the temperature was of -21.8 ºF.
- The change was of 17.3 ºF.
Hence:
On Friday, the temperature at Noon was of -4.5 ºF.
You can learn more about change at brainly.com/question/24313700