In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real
<span>The right tail is longer than the left.</span>
What you do here is subtract g from f: x^2 - 5x + 8 - (x^2 -4); x^2 - 5x + 8 - x^2 + 4; Rearranging gives you x^2 - x^2 - 5x + 8 + 4 which is, simplified, -5x + 12
the square root is 8.246211251
Hey there!
-2<3x+1
= 3x + 1 < -2
SUBTRACT 1 to BOTH SIDES
3x + 1 - 1 < -2 + 1
CANCEL out: 1 - 1 because that gives you 0
KEEP: -2 + 1 because that helps you solve for x
-2 + 1 = -3
New EQUATION: 3x > -3
DIVIDE 3 to BOTH SIDES
3x/3 > -3/3
CANCEL out: 3/3 because that gives you 1
KEE3 -3/3 because that helps us compare for x
-3/3 = -1
Answer to the equation: x > -1
OVERALL Answer: x > -1; It is an OPENED circle shaded to the right starting at -1 (Option A.)
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
