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faltersainse [42]
3 years ago
9

What is the slope of (-8,-3) and (4,-6)

Mathematics
1 answer:
jekas [21]3 years ago
8 0

The slope is -1/4.

Assuming you know the rise over run method, at point (-8, -3) you go down once (-1) and to the right 4 (+4) to get to the next point on the line. When you convert it to a fraction, the slope is -1/4.

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-7=21+x help please thankyou
serg [7]
Move the 21 to the other side and change the sign

-7-21=x
x=-28

hope this helps
4 0
3 years ago
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What two numbers will -2.5 be in between? <br> -2 and 1 <br><br> or<br><br> -3 and 2
tangare [24]

Answer:

It would be between -3 and 2

Step-by-step explanation:

cause -2.5 is greater than -3 and its less than 2

8 0
3 years ago
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in January, Dawn earns $9.25 allowance. She earns 3 times as much in February. If during March, she earns $5.75 more than she di
AURORKA [14]
Jan: 9.25
Feb: 9.25 x 3 = 27.75
March: 27.75 + 5.75 = 33.50

Dawn earns $33.50
8 0
3 years ago
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A square pyramid is shown sitting on its base.
sesenic [268]

Answer:

312

Step-by-step explanation:

First we find the measure of the basea and that is 144 becuase 12x12

To find one side we do b*h over 2 and that is 7x12/2 which is 42 then we know that there are 4 more of those sides and we get 42*4 168

When we add 144+168 we will get 312

5 0
3 years ago
"A study conducted at a certain college shows that 56% of the school's graduates find a job in their chosen field within a year
KiRa [710]

Answer:

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they find a job in their chosen field within one year of graduating, or they do not. The probability of a student finding a job in their chosen field within one year of graduating is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

56% of the school's graduates find a job in their chosen field within a year after graduation.

This means that p = 0.56

Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

This is P(X \geq 1) when n = 6.

Either none find a job, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.56)^{0}.(0.44)^{6} = 0.0073

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0073 = 0.9927

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

8 0
3 years ago
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