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egoroff_w [7]
3 years ago
9

2x(x - 3) + 7(x - 3) Can I have an explanation on how it works factors

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer:

Step-by-step explanation:

2x(x - 3) + 7(x - 3)

2x^2 - 6x + 7x - 21

reduce

2x^2 + x - 21

if this is equal to 0 then:

2x^2 + x - 21 = 0

factored:

(2x + 7)(x - 3) = 0

How that was done:

Divide the (2x^2) into (2x) and (x).

Divide the (-21) into (+7) and (-3). You choose these numbers so that their sum, when multiplied by (2x) and (-3), adds up to (+x).  

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3 0
3 years ago
A similarity transformation maps polygon ABCD to polygon PQRS. If the length of is 6 and the length of the corresponding side, ,
grigory [225]
For this case, what we must do is find the scale factor.
 We have then that the scale factor is given by:
 k =  \frac{L1}{L2}
 Where,
 L1: side length of polygon ABCD
 L2: side length of polygon PQRS
 Note: both sides belong to the same side of each polygon
 Substituting the values we have:
 k = \frac{6}{12}
 Rewriting we have:
 k = \frac{1}{2}
 Answer:
 
The scale factor of dilation is given by:
 
k = \frac{1}{2}
3 0
3 years ago
Read 2 more answers
Are my answers correct? Precalculus!!
SVETLANKA909090 [29]

Answer:

Unfortunately, your answer is not right.

Step-by-step explanation:

The functions whose graphs do not have asymptotes are the power and the root.

The power function has no asymptote, its domain and rank are all the real.

To verify that the power function does not have an asymptote, let us make the following analysis:

The function y = x ^ n , when x approaches infinity, where does y tend? Of course it tends to infinity as well, therefore it has no horizontal asymptotes (and neither vertical nor oblique)

With respect to the function y= \frac{1}{x} we ​​can verify that if it has asymptote horizontal in y = 0. Since when x approaches infinity the function is closer to the value 0.

For example: 1/2 = 0.5;   1/1000 = 0.001;    1/100000 = 0.00001 and so on. As "x" grows "y" approaches zero

Also, when x approaches 0, the function approaches infinity, in other words, when x tends to 0 y tends to infinity. For example: 1 / 0.5 = 2; 1 / 0.1 = 10; 1 / 0.01 = 100 and so on. This means that the function also has an asymptote at x = 0

6 0
3 years ago
6. The vertices of ALMN are L(7,4), M(7,16), and
max2010maxim [7]

Answer:

(a) LM=12 units, LN=35 units, MN=37 units

(b)8 84 units

(c) 210 square units

Step-by-step explanation:

(a)

Since points L and M have same x coordinates, it means they are in the same plane. Also, since the Y coordinates of L and N are same, they also lie in the same plane

Length LM=\sqrt {(7-7)^{2}+(16-4)^{2}}=12 units

Length LN=\sqrt {(42-7)^{2}+(4-4)^{2}}=35 units

LengthMN=\sqrt {(42-7)^{2}+(4-16)^{2}}=37 units

Alternatively, since this is a right angle triangle, length MN is found using Pythagoras theorem where

MN=\sqrt {(LN)^{2}+(LM)^{2}}=\sqrt {(12)^{2}+(35)^{2}}=37 units

Therefore, the lengths LM=12 units, LN=35 units and MN=37 units

(b)

Perimeter is the distance all round the figure

P=LM+LN+MN=12 units+35 units+37 units=84 units

(c)

Area of a triangle is given by 0.5bh where b is base and h is height, in this case, b is LN=35 units and h=LM which is 12 units

Therefore, A=0.5*12*35= 210 square units

4 0
3 years ago
What is the first step to solve this equation
shepuryov [24]

Answer:

First step, add 11 to 44.

Step-by-step explanation:

After that, divide both sides by negative 3.

7 0
3 years ago
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