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2 years ago

The dimensions of a 3-ft by 6-ft rectangle are multiplied by 1/3. How is the area affected?

1 answer:

3 0

The area will be 1/9 times the area of the normal dimension. Furthermore,
Area of the dimension:
3×6=18 square feet
Area of the scale drawing;
(3×1/3)(6×1/3)=2. Now, we see that the area of the scale drawing is 2/18 or 1/9 times the area of the normal dimension. Hope it help!

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Find the 14th term of the geometric sequence 7, 28, 112,

Fed [463]

Answer:

a(14)=469762048

Step-by-step explanation:

geometric sequence= a(n)=a*r^(n-1)

we have:

a=7

r=28/7=4

So:

a(14)=7*4^(14-1)

=7*4^(13)

=469762048

hope this helps

6 0

2 years ago

At 8:00 am the smiths left a camp ground, driving at 48 mi/h. At 8:20 am the Garcia's left the same campground and followed the

Fantom [35]

Answer:

9:40 am

Step-by-step explanation:

Let time taken from when Smith left compound to when Garcia overtakes Smith's car be represented by y

After y hours, Smith has covered 48*y=48y miles

Similarly, due to a difference of 20 minutes which is 20/60=1/3 hours, Garcia moves a distance of

60(y-1/3)

Equating both distances to be the same

60y-20=48y

12y=20

y=20/12=5/3 hours

Converted to minutes

5/3*60=100 minutes= 1 hr 40 mins

Therefore, adding 100 minutes to to starting time of Smith

8:00+1:40=9:40 am

The time that Garcia overtakes Smith is 9:40am

3 0

3 years ago

Which statement is true?

BlackZzzverrR [31]

For this problem, the answer is choice A.

3 0

3 years ago

Read 2 more answers

Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→1 1 − x + l

AfilCa [17]

$\displaystyle\lim_{x\to1}\frac{1-x+\ln x}{1+\cos5\pi x}$

Evaluating the limand directly at $x=1$ gives an indeterminate form $\dfrac00$ . Apply L'Hospital's rule once and we get

$\displaystyle\lim_{x\to1}\frac{-1+\frac1x}{-5\pi\sin5\pi x}$

Again, plugging in $x=1$ returns $\dfrac00$ . Apply the rule once more:

$\displaystyle\lim_{x\to1}\frac{-\frac1{x^2}}{-25\pi^2\cos5\pi x}=\frac1{25\pi^2}\lim_{x\to1}\frac1{x^2\cos5\pi x}$

Now, in the denominator, when $x=1$ we get $x^2\cos5\pi x=-1$ , so the limit is $-\dfrac1{25\pi^2}$ .

3 0

3 years ago

Need a little help here pls

Crank

Answer:

The statements that must be true are:

XY and JK form four right angles ⇒ B

XY ⊥ JK ⇒ C

JP = KP ⇒ E

m∠JPX = 90° ⇒ F

Step-by-step explanation:

From the given figure

∵ Line XY is the perpendicular bisector of the line segment JK

→ That means line XY is the line of symmetry of the line segment JK

∴ XY ⊥ JK ⇒ C

∵ XY ∩ JK at point P

∴ P is the midpoint of JK

∵ XY ⊥ JK

∴ ∠JPX, ∠KPX, ∠JPY, and ∠KPY are right angles

∴ XY and JK form four right angles ⇒ B

∵ The measure of the right angle is 90°

∴ m∠JPX = m∠KPX = m∠JPY = m∠KPY = 90°

∴ m∠JPX = 90° ⇒ F

∵ P is the midpoint of JK

∴ JP = KP ⇒ E

4 0

3 years ago