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Lisa [10]
3 years ago
10

Find the midpoint of the line segment whose endpoints are (2.6, 5.1) and (3, 4.7).

Mathematics
2 answers:
Tresset [83]3 years ago
5 0
(2.6, 5.1) \Rightarrow x_1=2.6,y_1=5.1
\\(3,4.7)\Rightarrow x_2=3,y_2=4.7
\\
\\x= \frac{x_1+x_2}{2}= \frac{2.6+3}{2}=2.8
\\
\\y=  \frac{y_1+y_2}{2}= \frac{5.1+4.7}{2}=4.9
\\
\\M(2.8,4.9)

Nimfa-mama [501]3 years ago
3 0

Answer:

(2.8, 4.9)

Step-by-step explanation:

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2 years ago
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tia_tia [17]

Answer:

5.25

Step-by-step explanation:

If CD is perpendicular to AB, a right angle is formed by the perpendicular lines at the base of the triangle. If we know that AB is 3 we can divided that by two to use half the triangle and create a right trianle with a base of 1.5 (half of 3) a height of rad 3 now all we have to do is use P-Thags to find AC which is the hypotenuse. After doing 1.5 squared + rad 3 squared = ac squared you will get the answer of AC = 5.25

7 0
3 years ago
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ehidna [41]

Answer:

x=13

Step-by-step explanation:

Switch sides:

2x−9=17

Add 9 to both sides:

2x−9+9=17+9

Simplify

2x=26

Divide both sides by 2:

2x/2 =26/2

Simplify to get the result.

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8 0
2 years ago
HELPPP!! Plzzzz can’t do any more points so 10
Anestetic [448]

3. Answer: a) RT

                   b) XZ

                   c) TS


4. Answer: a) 26

                  b) 58

                  c) 21.5

                  d) 127

<u>Step-by-step explanation:</u>

2(PT) = AE              2(CP) = AN                 2(CT) = EN

2(13) = AE               2(29) = AN                  2(CT) = 43

  26 = AE                  58  = AN                      CT  = 21.5


Perimeter = AE + AN + EN

                = 26 + 58 + 43

                = 127

4 0
3 years ago
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