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Grace [21]
2 years ago
12

The data set represents a month-to-month progression of gasoline prices over the course of several months in an

Mathematics
1 answer:
Mila [183]2 years ago
6 0

Answer:

A.) -0.015x² + 0.365x + 1.116

Step-by-step explanation:

Using a graphing calculator, the quadratic regression equation obtained for the data in the table is :

General form of a quadratic regression equation :

A + Bx + Cx²

A = 1.115714

Bx = 0.3647x

Cx² = - 0.015x²

Hence, rounding to the appropriate number of decimal places, the quadratic regression equation becomes ;

-0.015x² + 0.365x + 1.116

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Rashon has a dimes and y nickels. He has no less than 12 coins worth at most $0.95
Soloha48 [4]

A possible solution of the system of inequalities is 5 dimes and, 8 nickels

<h3>How to determine a possible solution?</h3>

From the question, the given parameters are:

Number of coins = Not less than 12

Worth = At most $0.95

Represent dime with x and nickels with y

So, we have the following inequalities

x + y >= 12

0.1x +0.05y <= 0.95

Next, we plot the graph of the inequalities (see attachment)

From the graph, we have a possible solution to be (5, 8)

This is so because this point is in the shaded region

Read more about inequalities at

brainly.com/question/25275758

#SPJ1

7 0
1 year ago
248 students went on a trip to the zoo 6 buses were filled with students how to travel in cars how many students were the bus?
DochEvi [55]
41 students were in each bus and a remainder of two students have to go in a car.
6 0
3 years ago
A rancher has 200 feet of fencing to enclose two adjacent corrals
Arturiano [62]

Answer:

a) Each corral should be 33⅓ ft long and 25 ft wide

b) The total enclosed area is 1666⅔ ft²

Step-by-step explanation:

I assume that the corrals have identical dimensions and are to be fenced as in the diagram below

Let x = one dimension of a corral

and y = the other dimension

 

(a) Dimensions to maximize the area

The total length of fencing used is:

4x + 3y = 200

4x = 200 – 3y

x = 50 - ¾y

The area of one corral is A = xy, so the area of the two corrals is

A = 2xy

Substitute the value of x

A = 2(50 - ¾y)y

A = 100 y – (³/₂)y²

This is the equation for a downward-pointing parabola:

A = (-³/₂)y² + 100y

a = -³/₂; b = 100; c = 0

The vertex (maximum) occurs at  

y = -b/(2a)  = 100 ÷ (2׳/₂) = 100 ÷ 3 = 33⅓ ft  

4x + 3y = 100

Substitute the value of y

4x + 3(33⅓) = 200

4x + 100 = 200

4x = 100  

x = 25 ft

Each corral should measure 33⅓ ft long and 25 ft wide.

Step 2. Calculate the total enclosed area

The enclosed area is 50 ft long and 33⅓ ft wide.

A = lw = 50 × 100/3 = 5000/3 = 1666⅔ ft²

6 0
3 years ago
1 + 3 - (8 * 334 * 123) = x<br><br> x = ?
il63 [147K]

Answer:

if, 1 + 3 - (8 * 334 * 123) = x

then, x = -328652

8 0
3 years ago
What is the formula of percentage?
Dvinal [7]

Step-by-step explanation:

The forumla of percentage is Part over Whole

5 0
3 years ago
Read 2 more answers
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