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Softa [21]
3 years ago
9

To rationalize the denominator 2 sqrt 10/ 3 sqrt 11 you should multiply the expression by which fraction

Mathematics
2 answers:
malfutka [58]3 years ago
7 0

Answer:

B

Step-by-step explanation:

To rationalise the denominator.

Multiply the numerator/denominator by the radical on the denominator.

The radical on the denominator is \sqrt{11}, thus

Multiply the fraction by

\frac{\sqrt{11} }{\sqrt{11} } → B

Nadusha1986 [10]3 years ago
4 0

Answer:

Answer is B on Edge

Step-by-step explanation:

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Help with this question, ASAP!!
Taya2010 [7]

Answer:

The answer to your question is: second option

Step-by-step explanation:

g(x) = x + 4

- This function is linear because the power of x is 1, if the power were a different number it would not be linear.

- As the sign of 4 is positive, it means that the function is translated 4 units up.

- A constant is when there is a number, for example +4 or -4, in this example the function also has a letter "X" so it is not a constant.

7 0
3 years ago
The local parts shop buys a machine that costs $500000. Its value depreciates exponentially each year by 10%. What is the machin
Svetach [21]
The answer is 250000
hope it helps please mark as brainliest
7 0
4 years ago
Find the distance between the two points in simplest radical form.<br> (-5,8) and (-3, 1)
elixir [45]

Given:

The two points are (-5,8) and (-3,1).

To find:

The distance between the given two points in simplest radical form.

Solution:

Distance formula: The distance between two points is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, the distance between (-5,8) and (-3,1) is

d=\sqrt{(-3-(-5))^2+(1-8)^2}

d=\sqrt{(-3+5)^2+(-7)^2}

d=\sqrt{(2)^2+(-7)^2}

d=\sqrt{4+49}

d=\sqrt{53}

Therefore, the distance between two points (-5,8) and (-3,1) is \sqrt{53} units.

3 0
3 years ago
What are the values of x in the equation 4x^2+4x-3=0
ludmilkaskok [199]
I have an answer and an explanation!

ANSWER:X=\frac{1}{2}   (or) x= \frac{-3}{2}


Explanation:

<span>{Let's solve your equation step-by-step.}
</span>4 x^{2} +4x-3=0

<span>{Step 1: Factor left side of equation.}
</span>(2x-1)(2x+3)=0

{<span>Step 2: Set factors equal to 0.}
</span>2x-1=0 (or) 2x+3=0<span>
</span>
3 0
3 years ago
How do I factor the equation in writing this question?
SCORPION-xisa [38]

Step-by-step explanation:

You are just replacing the 'n' with the number in the 'n box'.

So if this is the formula:

b(n) = 4 - (n \div 3)

then:

B(-3)= 4-(-3/3)

B(-3)= 4-( -1)

B(-3)= 4+1

B(-3)= 5

B(0)= 4-(0/3)

B(0)= 4-0

B(0)= 4

B(3)= 4-(3/3)

B(3)= 4-1

B(3)= 3

6 0
3 years ago
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