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riadik2000 [5.3K]
3 years ago
13

If a greyhound can run up to 50mi/h. How long would it take a greyhound to run 10 mi?

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

12 minutes

Step-by-step explanation:

(50miles/60 minutes)/5 = 10 miles/12 minutes

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Find the midpoint of the segment with the given endpoints. <br> ​(9​,9​) and ​(-1​,-3​)
katrin [286]

Answer is (4,3)

=============================

Add up the x coordinates to get 9+(-1) = 8. Divide this over two and we end up with 8/2 = 4

Repeat for the y coordinates: 9+(-3) = 6, which cuts in half to get 6/2 = 3

The midpoint is at (4,3)

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The midpoint formula is

\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right) where (x1,y1) and (x2,y2) are the endpoints.

6 0
3 years ago
At the beginning of the school year, there
melomori [17]

Answer: 6% decrease

Step-by-step explanation:

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Lucy watched TV for 25 of an hour on Monday. She watched 79 of an hour on Tuesday. What day did she spend more time watching TV?
notka56 [123]
Hello there,

Lucy watched more TV on Tuesday.

This is because 1 hour = 60 minutes.

so, 25% of 60 min = 15 min on Monday

and, 79% of 60 min = 47.7 min rounded gives 48 minutes on Tuesday...

Hope this answer helps. Good luck.


6 0
3 years ago
How many and what type of solutions does the equation have?<br> 5y2 = 187 – 4
Gennadij [26K]

Answer:

Two solutions.

5 0
3 years ago
Using diaries for many weeks, a study on the lifestyles of visually impaired students was conducted. The students kept track of
Hoochie [10]

Answer:

a) 0.1020

b) 0.7125

c) 7.64 hours

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.65, \sigma = 1.93

(a) What is the probability that a visually impaired student gets less than 6.2 hours of sleep?

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2 - 8.65}{1.93}

Z = -1.27

Z = -1.27 has a pvalue of 0.1020.

So the answer for a is 0.1020.

(b) What is the probability that a visually impaired student gets between 6.8 and 10.93 hours of sleep?

This is the pvalue of Z when X = 10.93 subtracted by the pvalue of Z when X = 6.8. So

X = 10.93

Z = \frac{X - \mu}{\sigma}

Z = \frac{10.93 - 8.65}{1.93}

Z = 1.18

Z = 1.18 has a pvalue of 0.8810.

X = 6.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.8 - 8.65}{1.93}

Z = -0.96

Z = -0.96 has a pvalue of 0.1685.

So the answer for b) is 0.8810 - 0.1685 = 0.7125.

(c) Thirty percent of students get less than how many hours of sleep on a typical day?

This is the value of X in the 30th percentile, that is, the value of X when Z has a pvalue of 0.30. So it is X when Z = -0.525, since this happens between Z = -0.53 and Z = -0.52.

Z = \frac{X - \mu}{\sigma}

-0.525 = \frac{X - 8.65}{1.93}

X - 8.65 = -0.525*1.93

X = 7.64

The answer for c is 7.64 hours.

3 0
3 years ago
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