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Ulleksa [173]
2 years ago
10

A cab charges a $4 initial fee and then $2.50 per mile. If the cab driver charged you $15.25, how many miles, m, did you travel?

Mathematics
1 answer:
RoseWind [281]2 years ago
7 0

Answer:

About 4 miles

Step-by-step explanation:

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For the given polynomials find the sum of the squares of the roots. P(x)=x^3-x^2-18x+k
slega [8]

\text{Given that,}\\\\P(x) = x^3 -x^2 -18x+k\\\\\text{If the roots are}~ \alpha, ~ \beta,~\text{and}~ \gamma, ~ \text{then},\\\\\alpha +\beta+\gamma= -\dfrac{(-1)}1 = 1\\\\\alpha \beta +\beta \gamma + \gamma \alpha= -\dfrac{18}1 = -18\\ \\\text{Now, sum of the  squares of the roots,}\\\\\alpha^2 + \beta^2 + \gamma^2 = ( \alpha + \beta + \gamma)^2 -2(\alpha \beta + \gamma \beta + \gamma \alpha)\\ \\~~~~~~~~~~~~~~~~~~=1^2 - 2(-18)\\\\~~~~~~~~~~~~~~~~~~=1+36\\\\~~~~~~~~~~~~~~~~~~=37

6 0
2 years ago
Identify az of this sequence: 0.25, 0.5, 0.75, 1, 1.25. 1.5
4vir4ik [10]
<h3><u>Question:</u></h3>

Identify a3 of this sequence: 0.25, 0.5, 0.75, 1, 1.25, 1.5,...a3=

<h3><u>Answer:</u></h3>

The third term of sequence is 0.75

a_3 = 0.75

<h3><u>Solution:</u></h3>

Given that, sequence is:

0.25, 0.5, 0.75, 1, 1.25. 1.5

Let us find the difference between terms

0.5 - 0.25 = 0.25\\\\0.75-0.5 = 0.25\\\\1.25-1=0.25\\\\1.5-1.25=0.25

This is a arithmetic sequence

Because the difference between any term and its immediately preceding term is always 0.25

In a arithmetic sequence,

a_1 = \text{ first term of sequnece }\\\\a_2 = \text{second term of sequnce }\\\\a_3 = \text{third term of sequnece }\\\\a_n = \text{ nth term of sequnce }

Thus, in the sequence 0.25, 0.5, 0.75, 1, 1.25. 1.5

a_3 = \text{ third term } = 0.75

Thus the third term of sequence is 0.75

5 0
3 years ago
A deck of cards contains RED cards numbered 1,2,3,4,5, BLUE cards numbered 1,2,3, and GREEN cards numbered 1,2,3,4,5,6. If a sin
Tatiana [17]

Answer: 1/52

Step-by-step explanation:

A deck of cards contains 52 cards

Red cards are numbered 1,2,3

Blue cards are numbered 1,2,3,4,5,6

Green cards are numbered 1,2

Number of Red card = 3

Number of blue card = 6

Number of Green card = 2

Let Pr(R) = Probability of picking a Red card

Let Pr(B) = probability of picking a blue card

Let Pr(G) = probability of picking a green card

Let Pr(RE) = Probability of picking a red even card

Let Pr(RO) = probability of picking a red odd card

Let Pr(BE) =probability of picking a blue even card

Let Pr(BO) = probability of picking a blue odd card

Let Pr(GE) = probability of picking a green even card

Let Pr(GO) = probability of picking a green odd card

Pr(R) = 3/52

Since we have 3 red cards,

Pr(RE) = 1/3

Pr(RO) =2/3

Pr(B) = 6/52

= 3/26

Since we have 6 blue cards ,

Pr(BE) = 3/6

= 1/2

Pr(BO) = 3/6

= 1/2

Pr (G) = 2/52

= 1/26

Since we have 2 green cards,

Pr(GE) = 1/2

Pr(GO) = 1/2

The probability of picking a Green card and an odd green card is

Pr(G) n pr(GO)

1/26 * 1/2

= 1/52

5 0
3 years ago
Help with this problem please
quester [9]

Answer:

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6 0
3 years ago
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patriot [66]
120,000 cm
1km=100,000cm

7 0
3 years ago
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